HELP PLEASE Graph the point (-2,3) and 3 more points using a slope of -1/2
1 answer:
The linear equation that represents the point (-2,3) and 3 more points with a slope of -1/2 is y = -1/2x + 2
<h3>How to graph the point (-2,3) and 3 more points using a slope of -1/2?</h3>The given parameters are
Slope, m = -1/2
Point, (x1, y1) = (-2, 3)
The linear equation is calculated as:
y = m(x - x1) + y1
Substitute the known values in the above equation
y = -1/2(x + 2) + 3
Expand
y = -1/2x - 1 + 3
Evaluate the sum
y = -1/2x + 2
This means that the linear equation that represents the point (-2,3) and 3 more points with a slope of -1/2 is y = -1/2x + 2
See attachment for the graph of the point and the three other points
Read more about linear functions at:
#SPJ1
You might be interested in