USING ROA FORMULA , ANSWER IS IN % FORM. IM STUMPED. THE ABC COMPANY HAS NET INCOMEO OF $56K, ASSETS AT THE BEGINNING OF THE YEA
1 answer:
You might be interested in
An arithmetic sequence with first term a, and a common distance d si as follows:
m, m+d, m+2d, m+3d, ...
(for example: 3, 8, 13, 18 .... m=3, d=5)
let
be the n'th term of the arithmeti sequence
m, m+d, m+2d, m+3d, ...
then
so it is clear that the n'th term, si given by :
compare the rule we found with the given rule A(n)=-3+(n-1)(-2.2)
it is clear that m=-3, and d=-2.2,
so the sequence
m, m+d, m+2d, m+3d, ...
becomes:
-3, -3-2.2, -3-2*2.2, -3-3*2.2, ....
so
-3, -5.2, -7.4, -9.6
the first term is -3, the fourth term is -9.6, the 10th term can be found by plugging in n=10 in the formula:
<span>A(10) = –3 + (10 – 1)(–2.2)=-3+9(-2.2)=-3-19.8=-22.8
remark, we could have use the formula directly and solve for A(1), A(4) and A(10),
but with the explanations we see how we find derive the formula, and makes it easier to derive, even when we don't remember it properly.
Answer:
1st term=-3
2nd term=-9.6
10th term = -22.8</span>
m, m+d, m+2d, m+3d, ...
(for example: 3, 8, 13, 18 .... m=3, d=5)
let
m, m+d, m+2d, m+3d, ...
then
so it is clear that the n'th term, si given by :
compare the rule we found with the given rule A(n)=-3+(n-1)(-2.2)
it is clear that m=-3, and d=-2.2,
so the sequence
m, m+d, m+2d, m+3d, ...
becomes:
-3, -3-2.2, -3-2*2.2, -3-3*2.2, ....
so
-3, -5.2, -7.4, -9.6
the first term is -3, the fourth term is -9.6, the 10th term can be found by plugging in n=10 in the formula:
<span>A(10) = –3 + (10 – 1)(–2.2)=-3+9(-2.2)=-3-19.8=-22.8
remark, we could have use the formula directly and solve for A(1), A(4) and A(10),
but with the explanations we see how we find derive the formula, and makes it easier to derive, even when we don't remember it properly.
Answer:
1st term=-3
2nd term=-9.6
10th term = -22.8</span>
Answer:
Either of the following square values:
Step-by-step explanation:
The three possible answers correspond to the square of the sides of the triangles via the Pythagorean theorem. And these are: