Question

a rectangular room is 4 times as long as it is wide and it's perimeter is 60 meters find the dimension of the room

Answer 1

To answer this problem we have to use two different variables. For example...

L = Length

W = Width

So we know that the definition of perimeter is

L + L + W + W (or all the sides added up)

Now we also know that The Length is 4 times longer than the width.

So we can write 4W to replace the L

So in the given equation we set up Replace every L with 4W

4W + 4W + W + W = 60 meters

now group our W's

10W = 60 divide both sides by 10 to get W to be alone

÷10   = ÷10 It cancels on the left side and we solve on the right side.

W = 6

So now that we know what the width equals we can find what the length equals .

Remember this?

4W = L (plug in 6 for W)

4(6) = L

So L = 24

Our dimensions of this rectangle are length 24, width 6.

Good Luck! :)

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