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svetoff [14.1K]
1 year ago
15

Nvm I don't need help

Mathematics
1 answer:
Snowcat [4.5K]1 year ago
5 0

Answer:

ok

Step-by-step explanation:

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suppose a consumer advocacy group would like to conduct a survey to find the proportion p of consumers who bought the newest gen
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The size of the sample they should take to estimate p with a 2% margin of error and 90% confidence is n = 1691.

In statistics, the margin of error is just the degree of a significant error in the outcomes of random sample surveys.

The formula of margin error is, E = z√((p-vector)(1 - (p-vector)) ÷ n)

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Now, the proportion is not given so adopt nominal (p-vector) = 0.05

The critical value at CL of 90% is 1.645.

Thus, making n the subject,

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n = 1.645²((0.5 × 0.5) ÷ 0.02²)

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