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marysya [2.9K]
3 years ago
13

What transformations occurred in y=−∣x∣+4

Mathematics
1 answer:
Sedaia [141]3 years ago
3 0

Answer:

the answer of y=-1×1+4 is y=3

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For an (x, y) table, the y-value represents the __?
Olin [163]

Answer:

The left side how I rmeber is you have to walk into the elavator efore going up!

Step-by-step explanation:

3 0
2 years ago
Can someone please help me I really need help it’s my last question
Svetach [21]

Answer:

x^2+11x+30

Step-by-step explanation:

This is a parallelogram.

Area of a parallelogram can be found with:

A=bh

Plug our values in.

A=(x+6)(x+5)

FOIL-

First: x*x=x^2

Outside: x*5=5x

Inside: 6*x=6x

Last: 6*5=30

x^2+5x+6x+30

Combine like terms.

x^2+11x+30

7 0
3 years ago
A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
3 years ago
HELP PLEASE!!! CLUELESS
statuscvo [17]
-3-8X≥9

Add 3 on both sides.

-8X≥12

Divide by negative 8 and flip the sign.

X≤-1.5

There isn't a number behind five, so I would just keep as is.

I hope this helps!
~kaikers
5 0
3 years ago
Subtract<br> (3x2 + 2x – 9) - (4x2 - 6x + 3)<br> Enter your answer, in standard form in the box.
ss7ja [257]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
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