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1 year ago

3x-1/5=x+1/3 pls help me

Mathematics

2 answers:

RoseWind [281]1 year ago

8 0

Answer:

x=4/15

Step-by-step explanation:

first you need to make common denominators for 1/5 and 1/3

the common denominator is 15

5*3=15, 3*5=15. 1*3=3, 1*5=5

new equation:3x-3/15=x+5/15

now subtract x from both sides: 3x-3/15=x+5/15

-x -x

2x-3/15=5/15

now you can add 3/15 to 5/15

2x=8/15

now for the last step, divide by 2 because there are 2 x's

2x/2=x 8/15 /2=4/15

x=4/15

Lelu [443]1 year ago

8 0

Answer:

4/15

Step-by-step explanation:

3x-1/5 = x+1/3

make a common denominator

3x -3/15 = x + 5/15

next you can take away one x from both sides

2x - 3/15 = 5/15

then we want to have x alone on one side and everything else on the other

2x = 5/15 + 3/15

2x = 8/15

1x = 8/15 ÷ 2

1x = 8/30

simplify that

x = 4/15

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Which is the graph of y= square root x - 5 - 1

professor190 [17]

Answer:

Graph D

Step-by-step explanation:

3 0

3 years ago

Help me please (no links please)

stich3 [128]

a) This part is already complete I think..

b) This is a cuboid and lateral surface area of cuboid is: 2(lb +bh + hl)

= 2( 10 × 3 + 3 × 7 + 7 × 10)

= 2(30 + 21 + 70)

= 2 × 121 = 242 cm²

Now, the area of top & bottom: lb

= 2 × 10 × 3

= 60 cm²

Neglecting the top & bottom surface area of cuboid:

= 242 - 60

= 180 cm²

c) The total surface area us 242.. I have already done that part above...

__________________________

If i have done something wrong.. please lemme know :)

7 0

3 years ago

A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken

mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

$X=1$ number of citrus trees that are infected with the citrus red mite.

$n=5$ random sample taken

$\hat p=\frac{1}{5}=0.2$ estimated proportion of citrus trees that are infected with the citrus red mite.

$p$ true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values would be given by: