The interval of 95% confidence, for normally distributed variables, is average +/- 2 * standard deviation:
(-2*standard deviation + average , average + 2*standard deviation)
(-2*18 + 62.5 , 2*18 + 62.5) = (-36 + 62.5 , 36 + 62.5) = (26.5 , 98.5)
Answer: option D)
It’s 500.
Explanation: If you would solve for that m^3 over m^2, you’d get m^1. So, m^1 is the square root of m^2, so you just take the square root of 250,000 to get 500. I really hope this helps!
The amount of the substance (At) at any time t is calculated through the equation,
At = (A0)(e^-kt)
where A0 is the initial amount and k is constant.
For the half-life,
ln (At / A0) = ln 0.5 = -k(5270 years)
The value of k is 1.3153x10^-4 / year.
Substituting this value to the same equation, where At = 0.25A0
ln 0.25 = -(1.3153 x 10^-4)(t)
The value of t from this equation is 10540 years. The closest value to this is letter A.
Answer:
y = 3x
Step-by-step explanation:
Answer:
A=$1, 114.91 is the answer. Hope this helps!
