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Marat540 [252]
1 year ago
15

A.) find the test statistic

Mathematics
1 answer:
Arada [10]1 year ago
5 0

Regarding the hypothesis tested in this problem, it is found that:

a) The test statistic is: t = 0.49.

b) The p-value is: 0.6297..

c) The null hypothesis is not rejected, as the p-value is greater than the significance level.

d) It appears that the students are legitimately good at estimating one minute, as the sample does not give enough evidence to reject the null hypothesis.

<h3>What is the test statistic?</h3>

The test statistic of the t-distribution is given by the equation presented as follows:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

In which the variables of the equation are given as follows:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the hypotheses.
  • s is the standard deviation of the sample.
  • n is the sample size.

The value tested at the hypothesis is:

\mu = 60

From the sample, using a calculator, the other parameters are given as follows:

\overline{x} = 62.47, s = 19.2, n = 15

Hence the test statistic is obtained as follows:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{62.47 - 60}{\frac{19.2}{\sqrt{15}}}

t = 0.49.

<h3>What are the p-value and the conclusion?</h3>

The p-value is obtained using a t-distribution calculator, with a two-tailed test, as we are testing if the mean is different a value, in this case 60, with:

  • 15 - 1 = 14 df, as the number of degrees of freedom is one less than the sample size.
  • t = 0.49, as obtained above.

Hence the p-value is of 0.6297.

Since the p-value is greater than the significance level of 0.01, the null hypothesis is not rejected, attesting to the ability of the students to estimate one minute.

More can be learned about the test of an hypothesis at brainly.com/question/13873630

#SPJ1

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The correct answer is C. 
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What is the radian measure of the smaller angle formed by the hands of a clock at 4 pm?
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On a clock, every 5 minutes is just another 30° angle deviation away from the 12th hour, hence 30° × 4 = 120°

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\frac{120\pi}{180}
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what is the example of a product that will have the same number of zeros in the factors and the products? what is one example of
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Answer:

  • same: 30×40 = 1200
  • different: 20×50 = 1000

Step-by-step explanation:

Same: 30×40 = 1200 . . . . . 2 zeros in the factors; 2 in the product

Different: 20×50 = 1000 . . . 2 zeros in the factors; 3 in the product

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Same: 0.3×0.4 = 0.12 . . . . no zeros in the factors; no zeros in the product

Different: 0.2×0.4 = 0.08 . . . no zeros in the factors; 1 zero in the product after the decimal point

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For a product, the number of zeros will be different if the combined factors of the numbers increase the number of factors of 10 beyond the sum of the factors of 10 of the numbers being multiplied.

<u>Example</u>: neither 2 nor 5 has a factor of 10, but their product does.

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For a product that is a decimal fraction, the number of leading zeros will increase if the product of the mantissas of the numbers is less than 10. The number of trailing zeros will increase under the conditions discussed above. (0.25×0.4 = 0.100)

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Here, the term "mantissa" is used to refer to the portion of the number written in scientific notation that multiplies the power of 10.

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2 years ago
A coordinate grid with 2 lines. The first line is labeled y equals negative StartFraction 7 over 4 EndFraction x plus StartFract
KengaRu [80]

Answer:

1) (2.2, -1.4)

2) (1.33, 1)

Step-by-step explanation:

Question 1)

Two lines, with their corresponding equations are given and we have to find the solution to the system of equations.

The given lines are:

Equation of Line 1:

y=\frac{-7}{4}x+\frac{5}{2}

This line passes through the points: (0, 2.5) , (2.2, -1.4)

Equation of Line 2:

y=\frac{3}{4}x-3

This line passes through the points (0, -3) , (2.2, -1.4)

By looking at the graph/given data we have to find the solution of these linear equations.

Remember that the solution of linear equations is an ordered pair, through which both the lines pass i.e. the point at which both the given lines intersect is the solution of the linear equations.

From the given data we can see that both the lines pass through one common point, (2.2, -1.4). Since, both lines pass through this point, this means this is the point of intersection of the lines and hence there solution.

So, the answer to this questions is (2.2, -1.4)

Question 2)

The given equations are:

y = 1.5x - 1                                        Equation 1

y = 1                                                  Equation 2

We can solve these equations by method of substitution.

Substituting the value of y from Equation 2, in Equation 1, we get:

1 = 1.5x - 1

1 + 1 = 1.5x

2 = 1.5x

x = 2/1.5

x = 1.33

y = 1

Thus, the solution of the given linear equations is (1.33, 1)

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