Answer:
3. (6 : -8)
4. (2 : -6)
5. (7 : -6)
Step-by-step explanation:
Answer:
Not a true statement.
Step-by-step explanation:
8(6-4)=12
8(2)=16, not 12.
First, "boxes of two sizes" means we can assign variables: Let x = number of large boxes y = number of small boxes "There are 115 boxes in all" means x + y = 115 [eq1] Now, the pounds for each kind of box is: (pounds per box)*(number of boxes) So, pounds for large boxes + pounds for small boxes = 4125 pounds "the truck is carrying a total of 4125 pounds in boxes" (50)*(x) + (25)*(y) = 4125 [eq2] It is important to find two equations so we can solve for two variables. Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x: x = 115 - y [from eq1] 50(115-y) + 25y = 4125 [from eq2] 5750 - 50y + 25y = 4125 [distribute] 5750 - 25y = 4125 -25y = -1625 y = 65 [divide both sides by (-25)] There are 65 small boxes. Put that value into either equation (now, which is easier?) to solve for x: x = 115 - y x = 115 - 65 x = 50 There are 50 large boxes.
Answer:
cos ∠CBD = - 4√41 / 41
Step-by-step explanation:
AB = 4 ΔABC = (4 x AC) / 2 = 10
AC = 5
BC = √5² + 4² = √41
cos ∠CBD = cos (180° - ∠CBA) = cos 180° cos ∠CBA + sin 180° sin ∠CBA
(cos 180° = - 1 sin 180° = 0 cos ∠CBA = 4 / √41 )
cos ∠CBD = (-1) x cos ∠CBA = - 4 / √41 = - 4√41 / 41
Correct Answer: 10 students have never visited another state
40/100 × 25 =
40 is out of 100 because percentages always is represented by 100 (cent)
cross out the zero's equally top and bottom
so it would become: 4/100 × 25 = 4 ×25 = 100
then add the denominator
100/10 is our final resolution
cross out the zeros evenly and answer will give you 10.
