Question

The great Khafre Pyramid, the second tallest and second largest of the three ancient pyramids of Egypt, is 448 feet tall, and the length of a side at the base is 706 feet. The base of the pyramid is a square. What is its volume, rounded to the nearest cubic foot?

Answer 1

The volume of a pyramid can be calculated with the following formula:

$\text{volume =}\frac{1}{3}\times(area\text{ of base)}\times height$

The base of the pyramid is a square, so its area will be:

$\begin{gathered} \text{area of base =side}\times side \\ \text{area of the base=706}\times706 \\ \text{area of base =}498,436\text{ ft²} \end{gathered}$

Let's plug that result in the formula for the volume:

$\begin{gathered} \text{volume}=\frac{1}{3}\times(498,496)\times448 \\ \text{volume}=74,433,109\text{ ft³} \end{gathered}$

So our final answer will be:

$\text{volume = 74,433,109 ft}^3$