What is the value of 3 minus (negative 2)?

Mathematics

1 answer:

earnstyle [38]2 years ago

5 0

Answer:

Step-by-step explanation:

3-(-2) will become positive 5. so number line will go towards positive 5.

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4 friends have more than 7 stickers and less than 13 stickers they share the stickers evenly how many stickers NEED HELP

mash [69]

Well, there can be two answers. So, plus 3 other friends (4 people total) are sharing stickers.
To answer this, all you need to do is count by four.
4 is not greater than 7 so can not be the answer
4+4 or 8 IS greater than 7 and less than 13 so it can be the answer
4+4+4 or 12 IS ALSO GREATER THAN 7 and less than 13 so it can be the answer
4+4+4+4 is 16 and is greater than 13 so it cannot be the answer
SO it is either 8 or 12 stickers

3 0

3 years ago

PLEASE HELP<br>Find the solution of this system of equations <br> -5x=-21+6y <br> -5x+y=-84

NeTakaya

-5x - 6y = -21
5x - y =. 84

-7y = 63

y= -9

-5x = -21 - 54

-5x = -75

x = 15

4 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$