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Ierofanga [76]
1 year ago
10

Solve the following system of equations. (Hint: Use the quadratic formula.) f(x) = 2x² 3x g(x)=-3x² + 20 (0.-10) and (1, 17) (-2

.2, 5.9) and (3.2, 0.9) (28.-3.0) and (-1.5, -1) (-2.2, 5.9) and (2.8, -3,0)

Mathematics
1 answer:
jasenka [17]1 year ago
4 0

The solution of the system of equation is the intersection point of the two quadratic equations, so we need to equate both equations, that is,

2x^2-3x-10=-3x^2+20

So, by moving the term -3x^3+20 to the left hand side, we have

5x^2-3x-30=0

Then, in order to solve this equation, we can apply the quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In our case, a=5, b=-3 and c=-30. So we get

x=\frac{3\pm\sqrt{(-3)^2-4(5)(-30)}}{2(5)}

which gives

\begin{gathered} x=2.76779 \\ and \\ x=-2.16779 \end{gathered}

By substituting these points into one of the functions, we have

f(2.76779)=-2.982

and

f(-2.16779)=5.902

Then, by rounding these numbers to the nearest tenth, we have the following points:

\begin{gathered} (2.8,-3.0) \\ and \\ (-2.2,5.9) \end{gathered}

Therefore, the answer is the last option

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