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prisoha [69]
3 years ago
14

A. y=82x + 998 b. y=247.7x - 335 c. y=743x - 1647 d. y=998x + 82

Mathematics
2 answers:
Elodia [21]3 years ago
4 0
Answer for this question is A 
MrMuchimi3 years ago
3 0
A is the answer for the question
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A field test for a new exam was given to randomly selected seniors. The exams were graded, and the sample mean and sample standa
swat32
All our answers lie in the above statement.

Confidence Level:
The creator claims that 9 out 10 students will have the average score in the said range. Or in other words we can say that the creator is 90% confident about the result of the field test. So the confidence level is 90%. 

Margin of Error:
The average score lies within 4% of 70%. This means the margin of error is 4% i.e. the average scores can deviate from 70% by 4% .

Confidence Interval:
Lower Limit = 70% - 4% = 66%
Upper Limit = 70% + 4% = 74%

Interpretation:
The exam creator is 90% confident that the average scores of seniors will be between 66% and 74%. 
4 0
3 years ago
Free
Aleksandr [31]

Answer:

tysm. Have a wonderful day...

6 0
3 years ago
Whats another way to write 8/5 as a fraction ?
sashaice [31]
16/10

All you have to do to get another way to write a fraction is double the original fraction.

For example...

1/2 = 2/4 = 4/8 = 8/16...
All these are half, 8/16 is the same as 1/2.

Hope this helped. Have a great night!
3 0
3 years ago
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Ice cream jejebbeheue
Effectus [21]

Answer:

Step-by-step explanation:

3 0
3 years ago
(1) 16 liters of kerosene is needed for 12 stoves 14
Nastasia [14]

9514 1404 393

Answer:

  12 liters

Step-by-step explanation:

The kerosene usage is assumed to be jointly proportional to the number of stoves and the number of hours. That is ...

  v = k·s·h . . . . . for s stoves running h hours

Then the value of k is ...

  k = v/(sh) = (16 L)/(12·14) = 2/21 . . . . liters per stove-hour

Then the volume of kerosene required for 7 stoves and 18 hours is ...

  v = (2/21)·s·h

  v = (2/21)(7)(18) = 12 . . . liters

6 0
3 years ago
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