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Andre45 [30]
4 years ago
5

9s - 5s + 2s - s Please explain how you did this question.

Mathematics
2 answers:
Maslowich4 years ago
4 0
Just add them as if it were normal then put the s behind it
masha68 [24]4 years ago
4 0
Just take out the s' to make it easier
So 9-5+2-1
9-5= 4
4+2=6
And then +1 is 7
And all you have to do is put the s back in so the answer is:
7s
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Find/solve for x in the image above
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the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th
Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : \text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. 13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130      (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. 9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270      (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups =\dfrac{\text{Sum of combined students}}{\text{combined students}}

=\dfrac{400}{40}=10

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0
3 years ago
Which is the correct answer?
vovangra [49]

B is the correct answer , it is incorrect.

5 0
3 years ago
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