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Andre45 [30]
3 years ago
5

9s - 5s + 2s - s Please explain how you did this question.

Mathematics
2 answers:
Maslowich3 years ago
4 0
Just add them as if it were normal then put the s behind it
masha68 [24]3 years ago
4 0
Just take out the s' to make it easier
So 9-5+2-1
9-5= 4
4+2=6
And then +1 is 7
And all you have to do is put the s back in so the answer is:
7s
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Step-by-step explanation:

The function x(t)=e^{5t} is infinitely differentiable, so it satisfies a infinite number of differential equations. The required answer depends on your previous part, so I will describe a general procedure to obtain the equations.

Using rules of differentiation, we obtain that x'(t)=5e^{5t}=5x \text{ then }x'-5x=0. Differentiate again to obtain, x''(t)=25e^{5t}=25x=5x' \text{ then }x''-25x=0=x''-5x'. Repeating this process, x'''(t)=125e^{5t}=125x=25x' \text{ then }x'''-125x=0=x'''-25x'.

This can repeated infinitely, so it is possible to obtain a differential equation of order n. The key is to differentiate the required number of times and write the equation in terms of x.

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