9s - 5s + 2s - s Please explain how you did this question.

Mathematics

2 answers:

Maslowich3 years ago

4 0

Just add them as if it were normal then put the s behind it

masha68 [24]3 years ago

4 0

Just take out the s' to make it easier
So 9-5+2-1
9-5= 4
4+2=6
And then +1 is 7
And all you have to do is put the s back in so the answer is:
7s

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In an experiment, a fair coin is tossed 13 times and the face that appears (H for head or T for tail) for each toss is recorded.

zalisa [80]

Answer:

1) 1 element

2) 13 elements

3) 22 elements

4) 40 elements

Step-by-step explanation:

1) Only one element will have no tails: the event that all the coins are heads.

2) 13 elements will have exactly one tile. Basically you have one element in each position that you can put a tail in.

3) There are ${13 \choose 2} = 78$ elements that have exactly 2 tails. From those elements we have to remove the only element that starts and ends with a tail and in the middle it has heads only and the elements that starts and ends with a head and in the 11 remaining coins there are exactly 2 tails. For the last case, there are ${11 \choose 2} = 55$ possibilities, thus, the total amount of elements with one tile in the border and another one in the middle is 78-55-1 = 22

4) We can have:

A pair at the start/end and another tail in the middle (this includes a triple at the start/end)

One tail at the start/end and a pair in the middle (with heads next to the tail at the start/end)

For the first possibility there are 2 * 11 = 22 possibilities (first decide if the pair starts or ends and then select the remaining tail)

For the second possibility, we have 2*9 = 18 possibilities (first, select if there is a tail at the end or at the start, then put a head next to it and on the other extreme, for the remaining 10 coins, there are 9 possibilities to select 2 cosecutive ones to be tails).

This gives us a total of 18+22 = 40 possibilities.

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PLEASE HELP! GIVING POINTS!

Alex777 [14]

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Masja [62]

Ok so
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Gre4nikov [31]

Answer:

$y + 2 = \frac{5}{4} (x + 4)$

Step-by-step explanation:

1) First, find the slope of the line. Take two points the line intersects and use them for the slope formula, $\frac{y_2-y_1}{x_2-x_1}$ . We already know the line intersects (-4, -2). Just choose any one of the points you can see the line intersecting (in this case, I chose (0,3)) and plug in its values, too. Then solve:

$\frac{(3)-(-2)}{(0)-(-4)} \\\frac{3+2}{0+4} \\\frac{5}{4}$

So, the slope is $\frac{5}{4}$ .

2) Now that you have the slope, plug in values for the point-slope formula, $y - y_1 = m (x - x_1)$ . In order to write a linear equation with it, the $x_1$ , $y_1$ , and $m$ have to be substituted for with real values. The $m$ represents the slope - which means that we should place $\frac{5}{4}$ there. The $x_1$ and $y_1$ represent the x and y values of a point - and the questions wants us to use (-4, -2), so substitute -4 for $x_1$ and -2 for $y_1$ :