All categories

1 year ago

Factor 403 – 102O 2x (2x - 5)O 2. (x - 5)O 23 (223 – 10)O x (x2 – 10x)

Mathematics

1 answer:

suter [353]1 year ago

3 0

We are asked to factor out the expression:

4 x^3 - 10 x

So we extract a factor of "2" from the numerical factors "4" and "10", and also a factor of "x" from each term,leading to:

2 x ( 2 x^2 - 5)

Therefore, please select the first answer option they give you in the list.

You might be interested in

Represents the puud x + 4y = 25.50 3x + 2y = 24.00

stiks02 [169]

Try these $3.75

$4.50

$4.95

$5.25

6 0

3 years ago

A recipe uses 100 g of flour, 100 g of sugar and 80 g of butter.

Maslowich

Answer:

600 butter : 2000 flour : 200 sugar : 400 currants = 72 cakes

120 cakes could be made with 1 kg of butter

Step-by-step explanation:

Here, 72 cakes = 6 dozen cakes

( since 12 cake = 1 dozen cake ).

a. First calculate quantity of each ingredient per dozen by dividing each by 1.5 (18/12).

• Butter - 150/1.5 = 100 g per dozen

For 6 dozen :

100g x 6 = 600 g

• Flour - 500/1.5 = 333.33 g per dozen

For 6 dozen :

333.33 g x 6 = 2000 g

• Sugar - 50/1.5 = 33.33 g per dozen

For 6 dozen :

33.33 x 6 = 200 g

• Currants - 100/1.5 = 66.67 g per dozen

For 6 dozen :

66.67 x 6 = 400 g

b. It is given that,

150g butter is required to make = 18 cakes

Then by using unitary method, we get,

1 g of butter is required to make = 18/150 cakes

Since, 1 Kg = 1000 g

Then,

1000 g of butter is required to make = (18/150) × 1000

= 120 cakes

Hence, with 1 kg of butter 120 whole cakes can be made.

Hope this answer helps you :)

Have a great day :)

Mark brainliest

4 0

2 years ago

Read 2 more answers

Translate to an equation and solve: 4 is the product of 8 and g. As see is 4/8

lord [1]

Answer:

sorry accidentally answered

Step-by-step explanation:

8 0

2 years ago

Will give brainpower and most points! thank you please help!

ollegr [7]

Answer:

See image and connect the lines using the coordinates.

Step-by-step explanation:

7 0

3 years ago

In 1990 the average family income was about $ 39 , 000 , and in 2010 it was about $ 70 , 768 . Let x = 0 represent 1990, x = 1 r

iren2701 [21]

Answer:

 $f(x) = 1588.4x + 39000$ 

$f(15) = 62826$

Step-by-step explanation:

Given

In 1990; Income= $39000

In 2010; Income= $70768

Solving (a): An equation in form of f(x) = ax + b

First, we need to determine the slope, a

$a = \frac{y_2 - y_1}{x_2 - x_1}$

Taking y as income and x as year index.

When x = 0; y = 39000

When x = 20; y = 70768

Substitute these values in the above formula

$a = \frac{70768 - 39000}{20 - 0}$

$a = \frac{31768}{20}$

$a = 1588.4$

Next, is to determine the formula using:

$y - y_1 = a(x - x_1)$

Considering :When x = 0; y = 39000, we have

 $y - 39000 = 1588.4(x - 0)$ 

 $y - 39000 = 1588.4x$ 

Make y the subject of formula

 $y = 1588.4x + 39000$ 

Express y as a function of x

 $f(x) = 1588.4x + 39000$ 

Solving (b): Income in 2005

In 2005, x = 15

So:

$f(x) = 1588.4x + 39000$ becomes

$f(15) = 1588.4 * 15 + 39000$

$f(15) = 62826$

3 0

3 years ago