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3 years ago

If two lines intersect , then they intersect in exactly one

Mathematics

1 answer:

GenaCL600 [577]3 years ago

6 0

Answer:

point?

Step-by-step explanation:

is this a question or a statement

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What is the solution of the system of equations? y = –3x + 8 y = –5x – 2

jekas [21]

$y=-3x+8 \\ y=-5x-2 \\ \\ -3x+8=-5x-2 \\ -3x+5x=-2-8 \\ 2x=-10 \\ x=- \frac{10}{2} \\ x=-5 \\ y=-3(-5)+8=15+8=23 \\ \\ \boxed{-5,23}$

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3 years ago

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At a conference for 500 people, 30% of the participants are French, 15% are Americans, 5% are Germans, and are of other national

Olenka [21]

As said before, 160 is the correct answer
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3 years ago

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What are more 1/3 miles or 1762 feets

Zigmanuir [339]

1762 feet would be 2 feet more. There are 5280 in a mile, divide that by three and get 1760 feet.

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3 years ago

Question 5: prove that it’s =0

mamaluj [8]

Answer:

Proof in explanation.

Step-by-step explanation:

I'm going to attempt this by squeeze theorem.

We know that $\cos(\frac{2}{x})$ is a variable number between -1 and 1 (inclusive).

This means that $-1 \le \cos(\frac{2}{x}) \le 1$ .

$x^4 \ge 0$ for all value $x$ . So if we multiply all sides of our inequality by this, it will not effect the direction of the inequalities.

$-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4$

By squeeze theorem, if $-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4$

and $\lim_{x \rightarrow 0}-x^4=\lim_{x \rightarrow 0}x^4=L$ , then we can also conclude that $\im_{x \rightarrow} x^4\cos(\frac{2}{x})=L$ .

So we can actually evaluate the "if" limits pretty easily since both are continuous and exist at $x=0$ .

$\lim_{x \rightarrow 0}x^4=0^4=0$

$\lim_{x \rightarrow 0}-x^4=-0^4=-0=0$ .

We can finally conclude that $\lim_{\rightarrow 0}x^4\cos(\frac{2}{x})=0$ by squeeze theorem.

Some people call this sandwich theorem.

6 0

3 years ago

HELP ME NOW ASAP PLEASE

sergejj [24]

Answer:

D. There are points on the graph with the same $x$ -coordinate but different $y$ -coordinate.

Step-by-step explanation:

A relation is a function if and only if each element of the range, corresponding with y-axis, is associated with only one element of the domain, corresponding with x-axis. In this case, the graphed relation is not a function, since for all element of the domain, except 0, are related to two distinct elements of the range.

Hence, correct answer is D.

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3 years ago