Answer:
9/4
Step-by-step explanation:
if you use cross multiplication you can see that it would cross eachother out and becom one plz vote brainliest
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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Answer:
A. Law of detachment
Step-by-step explanation:
The Law of detachment implies that when one condition is fulfilled the other cannot be and vice versa, then it is made the conclusion.
This condition is made the conclusion.
The Acute and Obtuse are detached of each other.
The acute angle is one in which the value of the angle is less than 90 degrees and obtuse angle is one in which the angle is greater than 90 degrees but less than 180 degrees.
Thus angles less than 90 degrees are acute and greater than 90 degrees are obtuse.
The conclusion of the given statement is valid based on the law of detachment as the condition has been made a conclusion.
Answer:
Soft Tacos = 2
Burritos= 3
Step-by-step explanation:
You
3 x 2 = 6
18 - 6 = 12
12/4= 3
You spent 6$ on soft tacos and 12$ on burritos.
Your friend
2 x 2 = 4
10-4 = 6
6/2 = 3
Your friend spent 4$ on soft tacos and 6$ on burritos.
I hope I explained this well.
The widest are the ones with smallest fraction so the answer is C.