The zeros and intercepts of the polynomial m^2 + 5m + 4 will be different.
<h3>Intercepts and zero of a function</h3>
A quadratic function is a function that has a degree of 2.
Given the following equation
f(m) = m^2 + 5m + 4
The x-intercept occurs at the point where f(m) is zero and same is applicable to the zeros of the function.
This shows that the zeros and intercepts of the polynomial m^2 + 5m + 4 will be different.
Learn more on intercepts here: brainly.com/question/1884491
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Answer:D no correlation
Step-by-step explanation:because if you were to draw a straight line, it wouldn’t be near all of the lines
Answer:
it is underfined because if you look closely there is no slope in the graph
So lets just assume that y = 1 since 2x is most likely an even number.
Then we can say that 2x = 8
8 divided by 2 is 4
so a point on this line could be (4,1)
Hope this helped
These are the steps, with their explanations and conclusions:
1) Draw two triangles: ΔRSP and ΔQSP.
2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).
3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.
4) The segment SP is common to both ΔRSP and Δ QSP.
5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.
Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q
