All categories

4 years ago

The line segment joins the complex numbers

Mathematics

1 answer:

wolverine [178]4 years ago

8 0

In the pictured graph, the X axis is labeled as real Axis and the Y axis is labeled as Imaginary axis.

The letter i after a number is considered an imaginary number.
So in the given numbers 2 +2i the w is the real number and 2i is the imaginary number, which is located at the dot labeled B.

-1 +3i, -1 is the real number and 3i is the imaginary number, which is located at the dot labeled A.

Line Segment AB is the correct answer.

You might be interested in

Line ab passes through points a(-6,6) and b(12,3). if the equation of the line is written in slope-intercept form, y=mx+b, then

gladu [14]

Answer: 5

Step-by-step explanation:

We have the equation of the line is of the form $y=-\frac{1}{6}x+b$ .

Substituting in the coordinates (12,3), we get that:

$3=-\frac{1}{6}(12)+b\\\\3=-2+b\\\\b=5$

6 0

2 years ago

Point AAA is at {(6, -6)}(6,−6)left parenthesis, 6, comma, minus, 6, right parenthesis and point CCC is at {(-6,-2)}(−6,−2)left

garik1379 [7]

Answer:

B(-3, -3)

Step-by-step explanation:

If a point O(x, y) divides line segment XY in the ratio of n:m and the endpoints of the segment are $X(x_1,y_1)\ and\ Y(x_2,y_2)$ , the coordinates of O is:

$x=\frac{n}{n+m}(x_2-x_1)+x_1 \\\\y=\frac{n}{n+m}(y_2-y_1)+y_1$

Given that A(6, -6) and C(-6, 2). Pont B is on AC such that:

AB = (3/4)AC

AB/AC = 3/4

Therefore point B divides the line AC in the ratio of 3:1. Let point B be at (x, y), therefore:

$x=\frac{3}{3+1}(-6-6)+6=\frac{3}{4}(-12)+6=-9+6=-3\\ \\y=x=\frac{3}{3+1}(-2-(-6))-6=\frac{3}{4}(4)-6=3-6=-3$

Therefore the location of B is at (-3, -3)

8 0

3 years ago

Someone please help a girl out ‍♀️

Kazeer [188]

Answer:

well 180-36= 144

and it has 4 sided

4 0

3 years ago

Which quadratic function is represented by the table ???

Ulleksa [173]

Answer:

B) f(x) = 3x² - 2x + 5

Step-by-step explanation:

To find the correct quadratic function that represents the table, you must substitute [x] into the quadratic function.

A) f(x) = 3x² + 2x - 5

B) f(x) = 3x² - 2x + 5

C) f(x) = 2x² + 3x - 5

D) f(x) = 2x² - 2x + 5

A. 3(-2)² + 2(-2) - 5 =

3(4) - 4 - 5

12 - 4 - 5

12 - 9

= 3

B. 3(-2)² - 2(-2) + 5 =

3(4) + 4 + 5

12 + 9

= 21

C. 2(-2)² + 3(-2) -5 =

2(4) - 6 - 5

8 - 11

= - 3

D. 2(-2)² + 2(-2) + 5 =

2(4) - 4 + 5

8 - 4 + 5

8 + 1

= 9

Your correct answer is: B

8 0

3 years ago

Which division problem is equivalent to 4/7

hram777 [196]

4 divided by 7
Remember a fraction is just a division problem

3 0

3 years ago

Read 2 more answers