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Zina [86]
3 years ago
15

Jack the kangaroo hopped 50 yards in the same time that a young kangaroo hopped 10 feet. How many more feet did Jack hop? ft

Mathematics
2 answers:
nasty-shy [4]3 years ago
4 0
Ack hopped a total of 150 feet, that is 140 over what the young kangaroo hopped
fiasKO [112]3 years ago
3 0
Distance Jack hopped = 50 yards
Distance Jack hopped = 50 x 3 = 150 feet

Distance young kangaroo hopped = 10 feet.

Difference = 150 - 10 = 140 feet
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This question is Incomplete

Complete Question

Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)

Answer:

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Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

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x = 5 bl/s

z = 5 - 6.20/1.58

z = -0.75949

The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)

Probability value from Z-Table:

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P(x>5) = 1 - P(x<5)

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= 0.77622

Approximately to 4 decimal places = 0.7762

The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762

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Step-by-step explanation:

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