The volume of the cross-section perpendicular to the solid is the amount of space in the cross-section
<h3>How to set up the integral?</h3>
The question is incomplete;
So, I will give a general explanation on how to set up a definite integral for volume of a solid
Assume the solid is a cone;
Using the disk method, the integral of the volume is:

Using the washer method, the integral of the volume is:
![V = \int\limits^a_b {\pi [R(x)^2 -r(x)^2 ]} \, dx](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5Climits%5Ea_b%20%7B%5Cpi%20%5BR%28x%29%5E2%20-r%28x%29%5E2%20%5D%7D%20%5C%2C%20dx)
Read more about volume integrals at:
brainly.com/question/18371476
In ∆ ABC and ∆ADC
AB=AD
AC=AC(common side)
BC=DC
So, ∆ABC and ∆ADC are congruent triangles,
so, m<ABC= m<ADC(corresponding angles of the congruent triangles)
x= 97°
(n^-3)^6=n^-18=1/n^18
the answer is D
since it's a square all sides are equal so
6.25 multiplied by 6.25
= 39.1 square feet
Answer:
-3x^2+6x-157
Step-by-step explanation: