59.96.
If you distribute 4 to 14.99 then you get the answer above.
Answer:
The values of 'x' are -1.2, 0, 0,
or
.
Step-by-step explanation:
Given:
The equation to solve is given as:

Factoring
from all the terms, we get:

Now, rearranging the terms, we get:

Now, factoring
from the first two terms and 6 from the last two terms, we get:

Now, equating each factor to 0 and solving for 'x', we get:

There are 3 real values and 2 imaginary values. The value of 'x' as 0 is repeated twice.
Therefore, the values of 'x' are -1.2, 0, 0,
or
.
Try using PEMDAS,
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
So just do the problem in that order.
The answer you put is correct