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777dan777 [17]
2 years ago
12

Determine the absolute maximum and

Mathematics
1 answer:
pochemuha2 years ago
4 0

Answer:

  • maximum: 17
  • minimum: -3

Step-by-step explanation:

You want the absolute extremes of the function f(x) = x³ -3x² +1 on the closed interval [-1/2, 4].

<h3>Extreme values</h3>

The extreme values will be either the turning points of the function or the ends of the interval. We must examine all of those. A graphing calculator is helpful for evaluating the function at various points.

<h3>Interval ends</h3>

  f(-1/2) = 1/8

  f(4) = 17

<h3>Turning points</h3>

The turning points are found where the derivative is zero.

  f'(x) = 3x² -6x = 3x(x -2)

This function is zero where the factors are 0, at x=0 and x=2.

  f(0) = 1

  f(2) = -3

The maximum value is found at the right end of the interval: f(4) = 17.

The minimum value is found at the right turning point: f(2) = -3.

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