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shtirl [24]
9 months ago
9

How you do this?? I don’t get it at allll

Mathematics
1 answer:
Sidana [21]9 months ago
5 0

The values are 5i, -4, 2√2i, -16, -50i and i.

<h3>What is an imaginary number?</h3>

An imaginary number is a number that, when squared, has a negative result, and is defined by its property i² = −1 or i = √-1.

Given are numbers,

1) √-25 = √25*√-1 = 5i

2) √-2√-2 = 2i*2i = 4i² = -4

3) √-8 = √8*√-1 = 2√2i

4) (4i)² = 16*i² = -16

5) (2i)(5i)² = 2i*25i² = 50i³ = -50i

6) i²*i³*i^{4} = -1*(-i)*1 = i

Hence, The values are 5i, -4, 2√2i, -16, -50i and i.

For more reference imaginary number, click;

brainly.com/question/6748860

#SPJ1

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⇒ \sqrt{[(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}]}
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5 seconds

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Using approciate properties find -4/7*3/5+4/7*-1/5+2/5*-4/5
slega [8]

Answer: 0.548

Step-by-step explanation:

First you need to remember the formula for PEMDAS(Parenthesis,exponents,multiplication,divison,addition,subtractio)

you can do either multiplication or divison whichever comes first, same with addition+subtraction.

the underlined means to simplify

1.<u>-0.57x3</u>/5+4/7x-1/5+2/5x-4/5

2.<u>-1.71/5</u>+4/7x-1/5+2/5x-4/5

3.-0.342+<u>4/7</u>x-1/5+2/5x-4/5

4.-0.342+0.57x<u>-1/5</u>+2/5x-4/5

5.-0.342+<u>0.57x-0.2</u>+2/5x-4/5

6.-0.342+0.114+<u>2/5</u>x-4/5

7.-0.342+0.114+<u>0.4x-4</u>/5

8.-0.342+0.114+<u>-1.6/5</u>

9.<u>-0.342+0.114</u>+-0.32

10.<u>-0.228+-0.32=-0.548</u>

<u>i did this all in one go so......</u>

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