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beks73 [17]
3 years ago
7

The ratio of boys to girls in the 9th grade is approximately 7 to 9. There are 228 girls. How many boys are there?

Mathematics
1 answer:
Keith_Richards [23]3 years ago
7 0

Answer:

Approximately 177 boys

Step-by-step explanation:

Let

x ----> the number of boys

y ----> the number of girls

we know that

\frac{x}{y}=\frac{7}{9}

isolate the variable x

x=\frac{7}{9}y ----> equation A

y=228 ----> equation B

substitute equation B in equation A

x=\frac{7}{9}(228)

x=177.33

therefore

Approximately 177 boys

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Solve for
Lubov Fominskaja [6]

Answer:

x = 3/2

Step-by-step explanation:

2(x + 5) = 6x + 4

Open bracket first

2 × x + 2×5 = 6x + 4

2x + 10 = 6x + 4

Rewrite equation

6x + 4 = 2x + 10

Subtract 2x from both sides

6x - 2x + 4 = 2x - 2x + 10

4x + 4 = 10

Subtract 4 from both sides

4x + 4 - 4 = 10 - 4

4x = 6

Divide both sides by 4

4x/4 = 6/4

x = 6/4

Divide both denominator and numerator by 2

x = (6/4) ÷ 2

x = 3/2

I hope this was helpful, please rate as brainliest  

7 0
3 years ago
How many and what type of solutions does the equation have?
Natali [406]
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81

Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
7 0
3 years ago
Read 2 more answers
A square has an area of 36 m2. The square is scaled in such a way that its area is increased by 28 m2. What is the approximate f
Roman55 [17]

Answer:

28/36 shd give u the answer

answer in 1:ur answer

4 0
3 years ago
What is the surface area of this triangular prism rounded to the nearest tenth? A) 48.6km2 B) 63.4 km2 C) 72.6 km2 D) 84.4 km2
Mekhanik [1.2K]

Correct option B)63.4km^2 .

<u>Step-by-step explanation:</u>

We have the following figure attached as shown below.

Now, this triangular prism have 2 similar right angled surfaces and 3 rectangular surfaces , Let's calculate area for all of them:

2 similar right angled surfaces

We know that area of triangle = \frac{1}{2} b(h)

⇒ area = \frac{1}{2} b(h)

⇒ area = \frac{1}{2} (3.6)(7.7)

⇒ area = 13.86km^{2}

But there 2 such surfaces so , area = 2(13.86) = 27.72km^2

3 rectangular surfaces

Area of rectangle = length(breadth)

⇒ area_1 = 3.6(1.8)

⇒ area_1 = 6.48km^2

⇒ area_2= 7.7(1.8)

⇒ area_2 = 13.86km^2

⇒ area_3 = 8.5(1.8)

⇒ area_2 = 15.3km^2

Total area =6.48 + 13.86 + 15.3 = 35.64km^2

Adding area of 2 similar right angled surfaces & 3 rectangular surfaces:

Area = 27.72+35.64 = 63.36km^2 = 63.4km^2

Correct option B)63.4km^2 .

4 0
3 years ago
Read 2 more answers
Solve the equation 4(x – 2) = 3x + 1. Question 15 options: A) 3 B) 8 C) 9 D) 2
telo118 [61]

Answer:

x = 9

Step-by-step explanation:

Step 1: Write equation

4(x - 2) = 3x + 1

Step 2: Solve for <em>x</em>

  1. <u>Distribute 4:</u> 4x - 8 = 3x + 1
  2. <u>Subtract 3x on both sides:</u> x - 8 = 1
  3. <u>Add 8 to both sides:</u> x = 9

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

  1. <u>Substitute:</u> 4(9 - 2) = 3(9) + 1
  2. <u>Parenthesis (add):</u> 4(7) = 3(9) + 1
  3. <u>Multiply:</u> 28 = 27 + 1
  4. <u>Add:</u> 28 = 28
5 0
3 years ago
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