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jeyben [28]
4 years ago
12

-6+k÷5=-9 how do we work this out

Mathematics
1 answer:
Step2247 [10]4 years ago
3 0
First you have to multiply both sides by -5 which means you will multiply -5 by 6, -5 by k/5, and -5 by 9... So it should look like: -5×6+-5×k/5=-5+9.. after that.. it should look like -40+k=-45.. because the 5's in k/5 cancel out.. so then it should now look like k=-45+30... you subtract.. and k=-15
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Bonjour je ne comprend pas cette exercice; si quelqu'un peut m'aider je suis preneuse.
gayaneshka [121]

Answer:

0,24 m

Step-by-step explanation:

La table est un rectanble donc l'angle en  haut à droite est de 90°.

Tu connais donc un angle et le côté opposé à l'angle et tu cherche le côté adjacent.

On sait que tan(â) = \frac{Cote oppose}{Cote adjacent} donc :

tan(40)= \frac{1,27}{x}

\frac{1,27}{tan(40)} = x

donc x ≈ 1,51 m

Le trou du mileu est à \frac{2,54}{2} soit 1,27m du bord.

Donc elle doit taper à 1,51 - 1,27 = 0,24m du trou du milieu.

j'espère avoir été clair.

<h2 />
8 0
2 years ago
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djverab [1.8K]

Answer:

Step-by-step explanation:

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7 0
3 years ago
For n = 10 and 1 = 0.59, what is P(X = 8)?
Arlecino [84]

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8 0
2 years ago
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elena-14-01-66 [18.8K]
Base area = 6 ( 1/2 x 6 x 5.2) = 93.6 cm²

Volume = base area x height = 93.6 x 17 = 1591.2cm ³

-------------------------------------------
Answer: Volume = 1591.2 cm³
-------------------------------------------
8 0
3 years ago
A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the
creativ13 [48]

Answer:

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

2r+s=18

s=r \theta

2r+r \theta=18

solve for r

r=\frac{18}{2+\theta}

step 2

Find the value of s

s=r \theta

substitute the value of r

s=\frac{18}{2+\theta}\theta

step 3

we know that

The area of complete circle is equal to

A=\pi r^{2}

The complete circle subtends a central angle of 2π radians

so

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}

substitute the value of r

A=\frac{(\frac{18}{2+\theta})^2\theta}{2}

A=\frac{162 \theta}{(\theta+2)^2}

Convert to function notation

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

6 0
4 years ago
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