Question

The length of a rectangle is five less than twice its width. If the perimeter is 62inches, find its dimensions.

Answer 1

Let L represent the length of the rectangle

Let W represent the length of the rectangle

The length of a rectangle is five less than twice its width. This means that

L = 2W - 5

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

Given that perimeter = 62, it means that

2(L + W) = 62

L + W = 62/2

L + W = 31

W = 31 - L

Substituting W = 31 - L into L = 2W - 5, it becomes

L = 2(31 - L) - 5

L = 62 - 2L - 5

L + 2L = 62 - 5

3L = 57

L = 57/3

L = 19

W = 31 - L = 31 - 19

W = 12

Length = 19 inches

Width = 12 inches