IM GIVING BRAINLIEST!!PLEASE HELP!!I PROMISE!!

1/2 + 2/3 / 1/6 help brainliest who answers first

NISA [10]

Answer:

Two answers are possible

Step-by-step explanation:

Both are listed below

8 0

3 years ago

A 99% confidence interval (in inches) for the mean height of a population is 65.7 < μ < 67.3. This result is based on a sa

Wittaler [7]

Answer:

$66.5 -1.976* 0.3065= 65.89$

$66.5 +1.976* 0.3065= 67.11$

And the 95% confidence interval would be givne by (65.89; 67.11)

Step-by-step explanation:

For this case we have a 99% confidence interval for the true mean hegiht givne by:

$65.7 \leq \mu \leq 67.3$

And we can begin finding the mean with this formula:

$\bar X= \frac{65.7 +67.3}{2}= 66.5$

Now we can estimate the margin of error:

$ME = \frac{67.3-65.7}{2}= 0.8$

The sample size for this case is $n = 144$ then the degrees of freedom are given by:

$df = n-1= 144-1=143$

And then we can find a critical value for a 99% of confidence and 143 degrees of freedom using a significance level of 0.01 and we got:

$t_{\alpha/2}= 2.61$

Then the standard error is given by:

$SE = \frac{ME}{t_{\alpha/2}}= \frac{0.8}{2.61}= 0.3065$

Now we can find the other critical value for 95% of confidence and we got:

$t_{\alpha/2}= 1.976$

And the new confidence interval would be given by:

$66.5 -1.976* 0.3065= 65.89$

$66.5 +1.976* 0.3065= 67.11$

And the 95% confidence interval would be givne by (65.89; 67.11)

3 0

3 years ago

A bacteria population increases every hour. at 12pm there are 5 cells at 1pm there are 10 cells at 2pm there are 20 cells and at

natita [175]

To solve you will have to multiply your answer by the number 2 the answer is 440

4 0

3 years ago

Read 2 more answers

What else would need to be congruent to show that ABC DEF by SAS? E AA. А B OA. BC = EF B. CF OC. ZA ZD D. AC = OF F Given: AC =

serg [7]

The two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.

Let $$&\overline{A B} \cong \overline{D E} \\$ and $$&\overline{A C} \cong \overline{D F}$

Angle between $\overline{A B}$ and $\overline{A C}$ exists $\angle A$ .

Angle between $\overline{D E}$ and $\overline{D F}$ exists $\angle D$ .

Therefore, $\triangle A B C \cong \triangle D E F$ by SAS, if $\angle A \cong \angle D$$ .

<h3>What is SAS congruence property?</h3>

Given:

$$&\overline{A B} \cong \overline{D E} \\$ and

$$&\overline{A C} \cong \overline{D F}$

According to the SAS congruence property, two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.

Let $$&\overline{A B} \cong \overline{D E} \\$ and $$&\overline{A C} \cong \overline{D F}$

Angle between $\overline{A B}$ and $\overline{A C}$ exists $\angle A$ .

Angle between $\overline{D E}$ and $\overline{D F}$ exists $\angle D$ .

Therefore, $\triangle A B C \cong \triangle D E F$ by SAS, if $\angle A \cong \angle D$$ .

To learn more about SAS congruence property refer to:

brainly.com/question/19807547

#SPJ9

4 0

2 years ago

I WILL MARK YOU AS BRAINLIEST IF YOU ANSWER THIS

kherson [118]

Answer:

Step-by-step explanation:

The way it is changed is by the way it looks and when it changes the cubes move with it so like in figure 2 there is only one missing and in the 3 one there ore four missing and in the last one only one is missing. So it is like a pattern it goes like 1,4,1,4,1. Like that. and the way you find the area of it is by multiplying the cube from each side so there are 36 cubes in the frist one and 35 in the second one and 32 in the 2rd one and in the last one there are 35. So you have yo multiply one side by the other side and the once you did it you will get your answer.

4 0

4 years ago