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Simora [160]
3 years ago
9

Do ya'll the answer to this problem well its not really a problem you have to write the equation.

Mathematics
1 answer:
AleksandrR [38]3 years ago
5 0

Z Z Z Z Z Z Z Z Z Z  Z Z Z  Z Z Z Z Z Z  Z Z  Z Z Z Z  Z Z Z  Z Z Z  Z

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Help please! I need help with question 3. I don’t know how to start it. I’ll give brainly☺️
ikadub [295]
First you divide $75 and 0.04. And that will get you the answer.
I already did this question last year.
6 0
3 years ago
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A classroom has students sitting in 5 columns of 5,6,7,5 and 2. What are the mean, median, mode, and range of class columns.
maria [59]
Mean: 5
Median: 5
Mode: 5
Range: 5
5 0
3 years ago
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Can someone check if my answers are right? I got 6,-18,54,-162,486,1458​
Lyrx [107]

Answer:

yes, you have it right except you need the 1458 negative

Step-by-step explanation:

Nice job getting them right!

8 0
2 years ago
What is 10/8 in simplest form
aliya0001 [1]
10/8 in simplest form:

First, we can start off by finding the GCF of the denominator and the numerator. To do so, we need to list the factors of each of them and find the common ones.

Factors of 10: 1, 2, 5, 10
Factors of 8: 1, 2, 4, 8

We can see that our common factors are 1 and 2, considering that both the numerator and denominator has the same factors (1 and 2). Since we have our common factors, we need to find the greatest. Which is the greatest out of 1 and 2? The GCF is 2 because it is bigger than 1.

Second, divide the numerator and the denominator by the GCF (2).
10 \div 2 = 5  \\ 8 \div 2 = 4

Third, now we can revise our fraction and turn it into the simplest form. Take the two numbers you just got above us and put them in their numerator and denominator spot. You should get: \frac{5}{4}

Answer in fraction form: \fbox {5/4}
Answer in decimal form: \fbox {1.25}
Answer in mixed number form: \fbox {1 1/4}
4 0
3 years ago
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Prove the following identity true. Show work.
yulyashka [42]

Answer:

The  Pythagorean identity states that

\sin^2 t + \cos^2 t = 1

Using that we can rewrite the left denominator as:

1 - \sin^2 t

Which can be factored as

(1 - \sin t)(1+ \sin t)

The numerator we can expand as:

(1 - \sin t)(1 - \sin t)

On the right hand side, let's multply numerator and denominator with (1 - sin t):

The total formula then becomes:

\dfrac{(1-\sin t)(1-\sin t)}{(1 - \sin t)(1 + \sin t)} = \dfrac{(1-\sin t)(1 - \sin t)}{(1+\sin t)(1 - \sin t)}

There you go... left and right are equal.

3 0
3 years ago
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