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Tanzania [10]
1 year ago
7

ok i have a chart that i have to right the line of best fit for and I don't know how to do that please help

Mathematics
1 answer:
stiv31 [10]1 year ago
8 0

You are looking for a line of the form

y=a+Bx

such that a,B minimize the distance between the given points and the line.

For that

B=\frac{\sum ^n_{k=1}(x_ky_k-\bar{y}x_k)}{\sum ^n_{k=1}(x^2_{^{}k}-\bar{x}x_k)}

and

a=\bar{y}-\bar{Bx}

Now we just have to apply the formula

after we apply it we get that

ŷ = 1.50473 x + 12.90922

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Mr. pham wrote the equation below on the board.
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18 - 7x = -20.5

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x = -38.5 / -7

x = -5.5 = 5 1/2

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7 0
3 years ago
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Answer:

A,D,E. Hope this helps!

Step-by-step explanation:

A. x=5

B. x=11

C. x=11/6

D. x=5

E. x=5

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3 years ago
How to find the value of x in degrees HELP
Marta_Voda [28]

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Step-by-step explanation:

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3 years ago
Which is the correct input-output table for the function f(x) = 3/x + 4
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7 0
3 years ago
The gross weight of a truck containing 30 pigs is 8 tons 1,123 pounds and 6 ounces. The average weight of one pig is 95 pounds 1
irakobra [83]

Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

The weight of the empty truck is 7 tons 254 pounds 10 ounces.

Step-by-step explanation:

Since we have given that

The gross weight of a  truck containing 30 pigs = 8 tons 1123 pounds 6 ounces

Average weight of one pig = 95 pounds 10 ounces

Now,

We know that

1\text{ pound}=16\text{ ounces}

So,

\text{Gross weight of truck containing 30 pigs}\\=8\text{ tones }1123\times 16+6\text{ ounces}\\=8\text{ tons }17974\text{ ounces}

Similarly,

\text{ average weight of one pig }\\=95\times 16+10\text{ ounces}\\=1530\text{ ounces}

So, Net weight of the pigs in the truck

1530\times 30\\ =45900\text{ ounces}\\\\=\frac{45900}{16}\\\\=2868\text{ pounds }12\text{ ounces}\\\\=1\text{ ton }868\text{ pounds }12\text{ ounces }

So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

Now, we'll find the weight of the empty truck is given by

\text{Gross weight of a truck containing} -\text{ Net weight of pigs in the truck}\\=8\text{ tons}1123\text{ pounds}6\text{ ounces}-1\text{ton }868\text{ pounds }12\text{ounces}\\=(8\times 2000\times 16+1123\times 16+6)-(1\times 2000\times 16+868\times 16-12)\\=273974\text{ ounces}-45900\text{ ounces}\\=228074\text{ounces }\\=7\text{ tons }254\text{ pounds }10\text{ ounces}

Hence, the weight of the empty truck is 7 tons 254 pounds 10 ounces .


4 0
3 years ago
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