Question

12.) tan L

Answer 1

Answer: $\frac{\sqrt{6}}{2}$

Step-by-step explanation:

By the Pythagorean theorem,

$2^2 + (MN)^2 = (\sqrt{10})^2\\\\4+(MN)^2 = 10\\\\(MN)^2 = 6\\\\MN=\sqrt{6}\\\\\implies \tan L=\frac{\sqrt{6}}{2}$