To answer this question, you should set up and equation before doing anything else. So for this question you 're going to set up two equations.
The first equation is 2x+5y=33
The second equation is 8x+3y=30
Once you do that you have to solve for either X or Y by canceling out the other one. In this problem figuring out the Y is easier because you can cancel the X's more easily than the Y. To cancel a variable, they have to add up to 0.
So to cancel the X you multiply the equation 2x+5y=33 by -4.
That gives you -8x-20y= -132
Then you set up the two equations and add them together.
(-8x-20y= -132) + (8x+3y=30)
That gives you -17y = -102
So then you solve for Y by dividing by -17. You find out that Y is equal to 6. Then you plug the 6 back into the ORIGINAL equations and solve for X, which turns out to be 1.5
Hope this helped and if you get confused or have questions please ask :)
Answer:
First Integer = n = 45
Second Integer = n+1 = 45 + 1 = 46
And Third Integer = n+ 2 = 45 +2 = 47
Step-by-step explanation:
Let First integer = n
Second Integer = n+1
Third Integer = n+2
According to the question given (If the first of three consecutive integers is subtracted from 138, the result is the sum of the second and third) the equation will be:
138 - n = (n+1) + (n+2)
Solving the equation:
138 - n = n+1+n+2
138 - n = 2n+3
138 - 3 =2n +n
135 = 3n
135/3 = n
=> n= 45
So, First Integer = n = 45
Second Integer = n+1 = 45 + 1 = 46
And Third Integer = n+ 2 = 45 +2 = 47
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Its a i just took the test
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