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3 years ago

Helpppppp meeeeee plzzzzzzz!!!!!

Mathematics

1 answer:

loris [4]3 years ago

3 0

50 is the answer if 30 is 60% of the club that means 10 is 20% and you just skip count until it reaches 100%

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Express the first quantity as a percentage of second quantity $45, $120.

Pachacha [2.7K]

Answer: 37.5%

Step-by-step explanation:

Percentage = Given Quantity/Total Quantity*100

So here, it will be like: 45/120*100

=0.375*100

=37.5%

5 0

2 years ago

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago

I need project on thales theorem

Naily [24]

Dont under stand put pitire so we can help u

7 0

3 years ago

Can someone help me find the answer?

raketka [301]

Answer:

AC=9 cm

ABC is not a right angled triangle

Step-by-step explanation:

AB=8cm

BC=5cm

22=AB+BC+AC

AC=22-8-5

AC=9

since AC is the longest,

using Pythagoras theorem

AC^2=BC^2+AB^2

9^2=8^2+5^2

81=64+25

81=89

therefore, it is not a right angled triangle

8 0

3 years ago

Read 2 more answers

A prism is completely filled with 3996 cubes that have edge lengths of 13 in. What is the volume of the prism? Enter your answ

ANEK [815]

First, solve for the volume of each cube through the equation,
V = e³
Substituting the known value,
V = (13 in)³ = 2197 in³
Then, multiply this volume by the number of cubes. Thus, the total volume of the prism,
V = (2197 in³)(3996)
V = 8,779,212 in³

3 0

3 years ago

Read 2 more answers