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ryzh [129]
8 months ago
14

You deposit $200 every quarter for 12 years into a sinking fund that pays 2.25% interest compounded annually. What is the future

value of your fund?
Mathematics
1 answer:
anzhelika [568]8 months ago
6 0

Answer:

$16,974.57

Step-by-step explanation:

The formula for future value  is given by

FV=PMT\frac{(1+i)^{n}-1}{i}

where

FV = future value

PMT = amount deposited each period and is given as 200

i = rate per period = r/m where r is the interest rate and m the frequency of compounding. Here it is mentioned that r = 2.25% and interest is compounded annually ie once per year so m = 1

i = 2.25%/1 = 2.25% = 2.25/100 = 0.0225

The number of payments n = 48 since we make quarterly payments (4 per year) and we are asked to compute for 12 years

Plugging these values into the formula gives

FV=200\frac{(1+0.0225)^{48}-1}{0.0225}

which evaluates to

$16,974.57 which can be rounded up to $16975

depending on the accuracy you desire

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-2 x 14 = -28

b is the answer

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here , in the given figure ;

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The Bureau of the Census reports the average commuting time for citizens of both Baltimore, Maryland, and Miami, Florida. To see
emmainna [20.7K]

Answer:

z=\frac{28.5-35.2}{\sqrt{\frac{7.2^2}{40}+\frac{9.1^2}{40}}}}=-3.652  

Now we can calculate the p value since we are conducting a bilateral test the p value would be:

p_v =2*P(z

Since the p value is very low we have enough evidence to reject the null hypothesis that the true means are equal at 5% of significance.

Step-by-step explanation:

Information provided

\bar X_{1}=28.5 represent the mean for Miami

\bar X_{2}=35.2 represent the mean for Baltimore

\sigma_{1}=7.2 represent the population standard deviation for Miami

\sigma_{2}=9.1 represent the population standard deviation for Baltimore

n_{1}=40 sample size selected for Miami

n_{2}=10 sample size selected for Baltimore

\alpha=0.05 represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value for the test

Hypothesis to analyze

We want to check if the commiting times are different in the winter for the two cities, so then the system of hypothesis are:

Null hypothesis:\mu_{1} = \mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

Since we know the population deviations the statistic for this case is given by:

z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)

Replacing the info provided we got:

z=\frac{28.5-35.2}{\sqrt{\frac{7.2^2}{40}+\frac{9.1^2}{40}}}}=-3.652  

Now we can calculate the p value since we are conducting a bilateral test the p value would be:

p_v =2*P(z

Since the p value is very low we have enough evidence to reject the null hypothesis that the true means are equal at 5% of significance.

6 0
3 years ago
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