Answer:
1/216
Step-by-step explanation:
x^(-3)y^(-3)
(2)^(-3)=1/2^3=1/8
(3)^(-3)=1/3^3=1/27
(1/8)(1/27)=1/216
Answer: recantagle
Step-by-step explanation:
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
miss girl-
Step-by-step explanation:
The answer is 5,600.00
Answer:
The joint probability of the two events is one.
Step-by-step explanation:
Complementary events:
If two events are complimentary, these three following things are true:
They are dependent.
The intersection of them is zero.
The joint probability of the two events is one.
The last one is the correct choice.