Question

Is the line through points p(-7,8) and q(-5,-6) parallel to the line throuh points R(3,-5) and S(-2,0)? explain.

Answer 1

Slope formula : (y2 - y1) / (x2 - x1)

(-7,8),(-5,-6)
slope = (-6 - 8) / (-5 - (-7) = - 14/(-5 + 7) = -14 / 2 = -7

(3,-5),(-2,0)
slope = (0 - (-5) / (-2 - 3) = (0 + 5) / -5 = -5/5 = -1

B. no, the lines have unequal slopes

Answer 2

I'm going to use the slope formula which is
m = (y2 - y1)/(x2 - x1)
where (x1,y1) and (x2,y2) are the two points the line goes through

Slope of line PQ
m = (y2 - y1)/(x2 - x1)
m = (-6 - 8)/(-5 - (-7))
m = (-6 - 8)/(-5 + 7)
m = (-14)/(2)
m = -7
The slope of line PQ is -7

Slope of RS
m = (y2 - y1)/(x2 - x1)
m = (0 - (-5))/(-2 - 3)
m = (0 + 5)/(-2 - 3)
m = (5)/(-5)
m = -1
The slope of line RS is -1

Because the slopes are NOT equal (one is -7 and the other is -1), this means the lines are NOT parallel.

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Answer: Choice B) No, the lines have unequal slopes