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1 year ago

Fill in the blanks in each rule.

Mathematics

1 answer:

Romashka [77]1 year ago

3 0

The ratio of their surface areas will be a²/b². And the ratio of their volumes a³/b³.

<h3>What are the surface area and the volume of an object?</h3>

The size is the amount of space covered by a two-dimensional hard surface.

The volume of an element or compound is the sufficient space it takes up, calculated in cubic units.

1. The ratio of the surface area of similar solids

If the ratio of the corresponding edge lengths of two similar solids is a:b, then the ratio of their surface areas will be a²/b².

2. The ratio of the volume of similar solids

If the ratio of the corresponding edge lengths of two similar solids is a:b, then the ratio of their volumes a³/b³.

More about the surface area and the volume link is given below.

brainly.com/question/15585435

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2 years ago

Read 2 more answers

-11=(x-3)÷2 what is the solution for x

e-lub [12.9K]

Answer:

-19

Step-by-step explanation:

~ Distribute:

- 11 = 1 / 2 x + -3 / 2

~ Flip the equation:

1 / 2 x + -3 / 2 = -11

~ Use transposition method:

(take -3 / 2 to the other side)

1 / 2 x = -11 - (-3 / 2)

= -19 / 2

x = -12 / 2 * 2

= -19

Hope this helped

Wishing u a gr8 day

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2 years ago

Kevin bicycles a total of 2,340 miles last year. On average, about how many miles did he bike each week? 195 45 44 46

svlad2 [7]

In order to find the average you have to add up all the data values and then find the sum of the data values.

$195 + 45 + 44 + 46 = 330\\\frac{330}{4} = 82.5\\\\$

So on average he ran about 82.5 miles.

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3 years ago

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vlada-n [284]

Answer:

Step-by-step explanation:

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3 years ago

For the region bounded by y=2x, the x-axis, and x=1, determine which of the following is greater: the volume of the solid ge

telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

$\int\limits^1_0 {(pi)y^{2} } \, dx$

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

$\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy$

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0

2 years ago