Answer:
The probability that one of the factory's bikes passed inspection and came off assembly line B is 0.564.
Step-by-step explanation:
Given : A bicycle factory runs two assembly lines, A and B. 97% of line A's products pass inspection and 94% of line B's products pass inspection. 40% of the factory's bikes come off assembly line B and the rest come off line A.
To find : The probability that one of the factory's bikes passed inspection and came off assembly line B ?
Solution :
The probability of line B's is P(B)= 40%=0.4
The probability of line A's is P(A)=100-40= 60%=0.6
Let E be the passes inspection.
The probability of line A's products pass inspection is P(E/A)=97%=0.97
The probability of line B's products pass inspection is P(E/B)=94%=0.94
The probability that one of the factory's bikes passed inspection and came off assembly line B is ![P(B\cap E)](https://tex.z-dn.net/?f=P%28B%5Ccap%20E%29)
![P(B\cap E)=P(B)\cdot P(E/B)](https://tex.z-dn.net/?f=P%28B%5Ccap%20E%29%3DP%28B%29%5Ccdot%20P%28E%2FB%29)
![P(B\cap E)=(0.6)(0.94)](https://tex.z-dn.net/?f=P%28B%5Ccap%20E%29%3D%280.6%29%280.94%29)
![P(B\cap E)=0.564](https://tex.z-dn.net/?f=P%28B%5Ccap%20E%29%3D0.564)
Therefore, The probability that one of the factory's bikes passed inspection and came off assembly line B is 0.564.
I think it is acute because below 90 is acute above 90 is obtuse and exactly 90 is right
Answer:
5 products are selected every hour.
Step-by-step explanation:
Giving the following information:
You work on a line where a finished product is selected every 12 minutes for inspection
<u>First, we structure the selection formula:</u>
y= x/12
y= number of products selected
x= number of minutes
<u>For 60 minutes:</u>
y= 60/12
y= 5 products
Answer:
a = - g/c + b/c
Step-by-step explanation:
use math-way :)