Question

LAST QUESTION ON THIS ASSIGNMENT I WILL GIVE BRAINLIEST

Answer 1

Good morning ☕️

Answer:

$S=7((-\frac{2}{5})^{n-1} - 1)$

Step-by-step explanation:

Consider

(Vn) the geometric Sequence

S the sum

q the common ratio

V1 the first term

$S=V_{1}\frac{1-q^{n-1} }{1-q}$

$q=\frac{2}{-5}=-\frac{2}{5} \\ \\V_1=-5$

then

$S=(-5)\frac{1-(-\frac{2}{5}) ^{n-1} }{1-(-\frac{2}{5} )}$

then (after a bit of calculations you’ll find)

$S=7((-\frac{2}{5})^{n-1} - 1)$

_______________________________

:)

Answer 2

Step-by-step explanation:

Hope it helps you in your learning process.