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2 years ago

Y=2x+10 find y if x=-2

Mathematics

1 answer:

mr_godi [17]2 years ago

3 0

$y=2x+10$

In order to find the value of y when x is equal to -2, we replace -2 in the equation

$y=2\cdot(-2)+10$

we start by solving the product first

$y=-4+10$

continue to add 10 to the result

$y=6$

y is equal to 6 when x is equal to -2

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3 years ago

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Mr. Smith invests a certain amount of money at 8% and twice as much at 5%. If his annual income from the two investments is $720

professor190 [17]

The amount invested by Mr.Smith in 5% is $240 .

Step-by-step explanation:

We have , Mr. Smith invests a certain amount of money at 8% and twice as much at 5%. If his annual income from the two investments is $720 . Let us suppose that Mr.Smith invest $x so :

Amount of money invested in 5% is $\frac{5x}{100}$ . And, amount of money invested in 8% is twice that of 5% i.e. $\frac{(2)5x}{100} = \frac{10x}{100}$ .

Now, total investment is $720 so,

$\frac{5x}{100}$ +( $\frac{(2)5x}{100} = \frac{10x}{100}$ ) = $720

⇒ $\frac{5x}{100} + \frac{10x}{100} = 720$

⇒ $\frac{15x}{100} = 720$

⇒ $\frac{100(720)}{15} = x$

⇒ $x = 4800$

The amount invested by Mr.Smith in 5% is $\frac{5x}{100}$ i.e. $\frac{5(4800)}{100} = 240$ . ∴ The amount invested by Mr.Smith in 5% is $240 .

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3 years ago

Divide it using the two methods.

den301095 [7]

Answer:

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3 years ago

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3 years ago

Graph the function with the given domain then identify the range of the function

alexira [117]

When the domain is ≥ to 0, that basically means that x must be ≥ 0.
Imagine what that looks like.
It would just be the right side of the coordinate plane, right? Because the left side would have negative x values.

We're basically just going to be graphing the line $y=3x-2$ , except only the part on the right side of the coordinate plane because of course x ≥ 0.

When you have an equation in the form of $y=mx+b$ , $b$ is going to be the y-intercept (the point where the line intersects the y-axis) and $m$ is going to be the slope.

Since the y-intercept is -2, draw a point at (0, -2).

Then, use the slope to find another point on the line.
The slope is 3, which as a fraction would be $\frac{3}1$ .
Slope = rise over run, so basically every change of 1 in x = a change of 3 in y.
Draw a point 3 up and 1 over from (0, -2). (at (1, 1))

Then draw a line through the two points we have graphed. Don't draw past the y-axis on the left side, because of course x ≥ 0.

And there you go!

The range of the function is basically the possible values y can have.
Well, since it's not going any lower than the y-intercept (0, -2), the range is ≥ -2.

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