Answer:
18049/14= 1289 with a remainder of 3
Answer:
less than
Step-by-step explanation:
6/9 is less than 9/12
6/9=.6666666666666666666666666
9/12=.75
.666666<.75
Answer:
the two numbers are 3 and 3.
1/5 of 3 is 0.6
1/5 of 6 is 1.2
Step-by-step explanation:
3 + 3 = 6
(1/5)3 = 0.6
(1/5)6 = 1.2
The distance between the Earth's surface and the upper edge of the Earth's atmosphere would be Q - V.
The distance from the Sun to the Earth is Q. The distance from the Sun to the upper edge of the atmosphere is V. If you subtract V from Q, the remaining distance is that of the Earth's atmosphere. Q - V = the atmosphere
Answer:
<em>There are approximately 114 rabbits in the year 10</em>
Step-by-step explanation:
<u>Exponential Growth
</u>
The natural growth of some magnitudes can be modeled by the equation:

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.
We are given two measurements of the population of rabbits on an island.
In year 1, there are 50 rabbits. This is the point (1,50)
In year 5, there are 72 rabbits. This is the point (5,72)
Substituting in the general model, we have:

![50=P_o(1+r)\qquad\qquad[1]](https://tex.z-dn.net/?f=50%3DP_o%281%2Br%29%5Cqquad%5Cqquad%5B1%5D)
![72=P_o(1+r)^5\qquad\qquad[2]](https://tex.z-dn.net/?f=72%3DP_o%281%2Br%29%5E5%5Cqquad%5Cqquad%5B2%5D)
Dividing [2] by [1]:

Solving for r:
![\displaystyle r=\sqrt[4]{\frac{72}{50}}-1](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B72%7D%7B50%7D%7D-1)
Calculating:
r=0.095445
From [1], solve for Po:



The model can be written now as:

In year t=10, the population of rabbits is:

P = 113.6

There are approximately 114 rabbits in the year 10