Answer:
2nd debate was 3 hours long.
Step-by-step explanation:
We have been given that during the mayoral election,two debates were held between the candidates. The first debate lasted 1 2/3 hours. The second one was 1 4/5 times as long as the first one.
Let us find the estimate of time spent on 2nd debate.
1 2/3 hours would be approximately 2 hours. 1 4/5 times would be equal to 2 times.
Therefore, the estimated time is less 4 hours.
To find the time spent on 2nd debate, we will multiply 1 2/3 by 1 4/5.
First of all, we will convert mixed fractions into improper fractions as:
Now, we will multiply both fractions as:
Therefore, the 2nd debate was 3 hours long.
Answer:i dont think so
Step-by-step explanation:
Answer:
There are 7 sides.
Step-by-step explanation:
Let's Use the formula that states that the sum of the angles of an n-sided polygon is given by.
S=(n−2)180
Since we are given that the two angles are right, the angles and each of the remaining angles is 144.
And Therefore, the sum is:
S=90
(n−2)144
(n−2)180
=90
+90
+(n−2)144
⇒(n−2)180
−(n−2)144
=180
⇒(n−2)(180
−144
)=180
⇒(n−2)(36
=180
⇒n−2=
36
180
⇒n−2=5
⇒n=5+2=7
Hence, the polygon has 7 sides.
Answer:
Step-by-step explanation:
Let q represent the number of quarters (the higher-value coin). Then 8-q is the number of dimes, and Jill's total amount in change is ...
0.25q +0.10(8-q) = 1.25
0.15q + 0.80 = 1.25 . . . . . . . eliminate parentheses
0.15q = 0.45 . . . . . . . . . . . . . subtract 0.80
q = 3 . . . . . . . . . . . . . . . . . . . . divide by 0.15
the number of dimes is 8-q = 8-3 = 5.
Jill has 3 quarters and 5 dimes.
The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx 28.27 sq in.
Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.
The difference is 52.73 sq in; the square is larger, the circle smaller.
