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3 years ago

Which is the correct input-output table for the function g(x)=-1/2(4x+6)

Mathematics

1 answer:

Sonbull [250]3 years ago

4 0

Answer: The third choice.

Step-by-step explanation: To find the first output, start with your first input. In this case, it's -2, so your equation would be g(-2)= -1/2(4(-2)+6). Start by solving inside the parenthesis. 4x-2=-8 and -8+6=-2. -1/2x-2= 1, so your first output should be 1. The only choice that has this is the third one, so that is your answer. Hope I could help :)

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Please help! The radius of a sphere is claimed to be 3.0 inches, correct to within 0.01 inch. Use linear approximation to estima

Vilka [71]

Answer:

0,36π inches³ or simply 1.13 inches³

Step-by-step explanation:

In this case, first, we need to calculate the volume of the sphere with the formula:

V = 4πr³/3

Replacing the data we have:

V = 4π(3)³/3

V = 36 in³

Now that we have the volume we need to calculate the resulting error. In this case, using linear approximation we have to use the derivates of V and r, so we have the following:

If V = 4πr³/3

Then the derivate of V (dV) would be:

dV = 4π*3*r²/3 dr

Where dr is the error of radius so:

dV = 4π*r² dr

Solving for dV:

dV = 4*3.14*(3)²*(0.01)

dV = 1.13 in³

So at the end, we just report the volume of the sphere as

V = 36 ± 1 in³

dV =

3 0

3 years ago

Solve: 1/5x = -10 A) -50 B) -20 C) -2 D) 2

Ede4ka [16]

Answer: A. x= -50

Step-by-step explanation:

1/5x = -10

1 = -10

1.1 = 5x. (-10)

- 50x

x= -50

6 0

4 years ago

What temperature is 10 degrees less then 6 degrees celsius

choli [55]

F=(9*6/5)+32

F=54/5+32

10.8+32

42.8

42.8-10=32.8

4 0

3 years ago

Help please solve <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1

Shkiper50 [21]

Answer:

$\displaystyle -\frac{1}{2} \leq x < 1$

Step-by-step explanation:

Inequalities

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

$\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0$

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

$\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0$

Simplifying by x-1 and taking x=1 out of the possible solutions:

$\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0$

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

$(6x^3+14x^2+10x+12)$

is always positive and doesn't affect the result. It can be neglected. The expression

$(x-\frac{1}{2})^2$

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

$\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0$