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notka56 [123]
3 years ago
12

Two objects are moving along separate linear paths where each path is described by position, d, and time, t. The variable d is m

easured in meters, and the variable t is measured in seconds. The equation describing the graph of the position of the first object with respect to time is d = 2.5t + 2.2. The graph of the position of the second object is a parallel line passing through (t = 0, d = 1). What is the equation of the second graph?
d = 2.5t + 1

d = t + 2.5

d = -0.4t + 1

d = 2.5t + 3.2
Mathematics
1 answer:
Marina86 [1]3 years ago
5 0
The second graph has the same slope of the first (because they are parallel), which is 2.5 and d-intercept of 1.

Then the second equation is d = 2.5t + 1.

 
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<h3>The maximum height of the tray</h3>

The distorted information (i.e. the function) in the question is:

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Differentiate the function

h'(t) = -0.4t + 0.4

Set to 0

-0.4t + 0.4 = 0

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In (a), we have:

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This represents the time to reach the maximum height.

The time spent in the air is:

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