Answer:
40 in^2
Step-by-step explanation:
Separate the shape into a square and a triangle. Find the measurements of each shape then find the sum.
Answer:
The answer is C. Domain is the y-axis and the Range is x-axis.
Answer:
3.84% of months would have a maximum temperature of 34 degrees or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 29.9, \sigma = 2.31](https://tex.z-dn.net/?f=%5Cmu%20%3D%2029.9%2C%20%5Csigma%20%3D%202.31)
What percentage of months would have a maximum temperature of 34 degrees or higher?
This is 1 subtracted by the pvalue of Z when X = 34. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{34 - 29.9}{2.31}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B34%20-%2029.9%7D%7B2.31%7D)
![Z = 1.77](https://tex.z-dn.net/?f=Z%20%3D%201.77)
has a pvalue of 0.9616
1 - 0.9616 = 0.0384
3.84% of months would have a maximum temperature of 34 degrees or higher
90% of what is 63....
0.90x = 63
x = 63 / 0.90
x = 70....so 70 ppl work at stalling printing
Actually I didn't see the (-5, -27), the answer would be -2.