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Wittaler [7]
3 years ago
5

PLZZZZZZZZ HURRY

Mathematics
2 answers:
Leya [2.2K]3 years ago
5 0

Step-by-step explanation:

option A (0,1) point will lie on the y axis as on y axis x coordinates is 0.

Fed [463]3 years ago
4 0

Answer:

0,1 lies on y axis ......

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Step-by-step explanation:

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What is the value of a?
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Actually, the answer is not A, if you're saying A is the first choice above.  That's incorrect.  You will need to use the Geometric mean for right triangles here to figure out what the value of a is.  We will use this form: \frac{YZ}{WZ} = \frac{WZ}{XZ}.  We have a value for YZ of 3; side a is XZ.  That means in order to solve this we need WZ, which we can find using pythagorean's theorem.  3^2 + 4^2 = c^2 and 9 + 16 = c^2 and c = 5.  Now we fill in accordingly: \frac{3}{5}= \frac{5}{XZ}.  Cross-multiply to get 3XZ=25 and side XZ is \frac{25}{3}.  XZ is 25/3 and YZ is 3, so 25/3 - 3 = XY.  That means that XY (side a) = 16/3 or 5 1/3, choice B, or the second one down.
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valina [46]
The answer is A or I
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Find the measure of angle eight in each triangle round each answer to the nearest 10th
vlada-n [284]

Answer:

# m∠A = 65.3°

# m∠A = 25.8°

# m∠A = 22.7°

Step-by-step explanation:

* Lets revise the trigonometry function to solve the problem

- In any right angle triangle:

# The side opposite to the right angle is called the hypotenuse

# The other two sides are called the legs of the right angle

* If the name of the triangle is ABC, where B is the right angle

∴ The hypotenuse is AC

∴ AB and BC are the legs of the right angle

- ∠A and ∠C are two acute angles

- For angle A

# sin(A) = opposite/hypotenuse

∵ The opposite to ∠A is BC

∵ The hypotenuse is AC

∴ sin(A) = BC/AC

# cos(A) = adjacent/hypotenuse

∵ The adjacent to ∠A is AB

∵ The hypotenuse is AC

∴ cos(A) = AB/AC  

# tan(A) = opposite/adjacent

∵ The opposite to ∠A is BC

∵ The adjacent to ∠A is AB

∴ tan(A) = BC/AB

* Lets solve the problems

# In Δ ABC

∵ m∠B = 90°

∵ AB = 2.3 ⇒ adjacent to angle A

∵ BC = 5 ⇒ apposite to angle A

- To find m∠A use the tangent function because we have opposite

  and adjacent sides

∴ tan A = BC/AB

∴ tan A = 5/2.3 ⇒ use tan^-1 to find m∠A

∴ m∠A = tan^{-1}\frac{5}{2.3}=65.29756

* m∠A = 65.3°

# In Δ ABD

∵ m∠B = 90°

∵ AB = 5.4 ⇒ adjacent to angle A

∵ DA = 6 ⇒ the hypotenuse

- To find m∠A use the cosine function because we have adjacent

  and hypotenuse sides

∴ cos A = AB/DA

∴ cos A = 5.4/6 ⇒ use cos^-1 to find m∠A

∴ m∠A = cos^{-1}\frac{5.4}{6}=25.84193

* m∠A = 25.8°

# In Δ ABE

∵ m∠B = 90°

∵ EB = 2.4 ⇒ opposite to angle A

∵ EA = 6.8 ⇒ the hypotenuse

- To find m∠A use the sine function because we have opposite

  and hypotenuse sides

∴ sin A = EB/EA

∴ sin A = 2.4/6.8 ⇒ use sin^-1 to find m∠A

∴ m∠A = sin^{-1}\frac{2.4}{6.8}=22.6673

* m∠A = 22.7°

3 0
3 years ago
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