Answer with Step-by-step explanation:
We are given that u and v are functions of x and both are differentiable at x=0
a.We have to find the values of 
Using this formula
Then , we get
![[\frac{d(uv)}{dx}]_{x=0}=u'(0)v(0)+u(0)v'(0)=7(2)+4(1)=14+4=18](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28uv%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3Du%27%280%29v%280%29%2Bu%280%29v%27%280%29%3D7%282%29%2B4%281%29%3D14%2B4%3D18)
![[\frac{d(uv)}{dx}]_{x=0}=18](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28uv%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D18)
b.
![[\frac{d(u/v)}{dx}]_{x=0}=\frac{u'(0)v(0)-u(0)v'(0)}{v^2(0)}=\frac{7(2)-4(1)}{2^2}=\frac{14-4}{4}=\frac{10}{4}=\frac{5}{2}](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28u%2Fv%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D%5Cfrac%7Bu%27%280%29v%280%29-u%280%29v%27%280%29%7D%7Bv%5E2%280%29%7D%3D%5Cfrac%7B7%282%29-4%281%29%7D%7B2%5E2%7D%3D%5Cfrac%7B14-4%7D%7B4%7D%3D%5Cfrac%7B10%7D%7B4%7D%3D%5Cfrac%7B5%7D%7B2%7D)
![[\frac{d(u/v)}{dx}]_{x=0}=\frac{5}{2}](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28u%2Fv%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D%5Cfrac%7B5%7D%7B2%7D)
c.
![[\frac{d(v/u)}{dx}]_{x=0}=\frac{v'(0)u(0)-v(0)u'(0)}{u^2(0)}=\frac{1(4)-7(2)}{4^2}](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28v%2Fu%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D%5Cfrac%7Bv%27%280%29u%280%29-v%280%29u%27%280%29%7D%7Bu%5E2%280%29%7D%3D%5Cfrac%7B1%284%29-7%282%29%7D%7B4%5E2%7D)
![[\frac{d(v/u)}{dx}]_{x=0}=\frac{-10}{16}=\frac{-5}{8}](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28v%2Fu%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D%5Cfrac%7B-10%7D%7B16%7D%3D%5Cfrac%7B-5%7D%7B8%7D)
d.
![[\frac{d(-6v-9u)}{dx}]_{x=0}=-6v'(0)-9u'(0)=-6(1)-9(7)=-6-63=-69](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28-6v-9u%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D-6v%27%280%29-9u%27%280%29%3D-6%281%29-9%287%29%3D-6-63%3D-69)
![[\frac{d(-6v-9u)}{dx}]_{x=0}=-69](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28-6v-9u%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D-69)
Here's an example...
So, in our last example...
In the point ( -2, -1 ), x1 = -2 and y1 = -1 ... and, in the point ( 4, 3 ), x2 = 3 and y2 = 3
m = ( y2 - y1 ) / ( x2 - x1 ) = ( 3 - ( -1 ) ) / ( 4 - ( -2 ) ) = 4 / 6 = 2 / 3
But, notice something cool...
The order of the points doesn't matter! Let's switch them and see what we get:
In the point ( 4, 3 ), x1 = 4 and y1 = 3 ... and, in the point ( -2, -1 ), x2 = -2 and y2 = -1
m = ( y2 - y1 ) / ( x2 - x1 ) = ( -1 - 3 ) / ( -2 - 4 ) = -4 / -6 = 2 / 3 ... Same thing!
Let's try our new formula with the second example in the last lesson:
It was a line passing through
( -1, 4 ) and ( 2, -2 )
m = ( y2 - y1 ) / ( x2 - x1 ) = ( -2 - 4 ) / ( 2 - ( -1 ) ) = -6 / 3 = -2
Answer:
a
Step-by-step explanation:
We have to find the greatest possible number of each type of flower
( pansies and daisies ) in each row.
We have to find the GCF for 27 and 36.
27 = 9 * 3
36 = 9 * 4
So : GCF ( 27, 36 ) = 9
We will have 9 pansies in 3 rows and 9 daisies in 4 rows.
Answer:
The greatest possible number of pansies in each row is 9.
Answer:
Step-by-step explanation:
