Question

Consider this equation y=-1/2x+4 1/2 and 3x - 4y = 12 solve the system by graphing. label each graph

Answer 1

On solving the equations y = (-1/2)x + $4\frac{1}{2}$ and 3x - 4y = 12 graphically , the solution is (6 , 3/2) .

In the question ,

it is given that

the equations are y = (-1/2)x + $4\frac{1}{2}$  and 3x - 4y = 12

which can be written as y = (-1/2)x + 9/2  and 3x - 4y = 12

to plot the graph of the given equations , we need intercept .

For the equation y = (-1/2)x + 9/2

when x= 0  , y = (-1/2)(0) + 9/2 = 9/2

when y = 0 ,

0 = (-1/2)x + 9/2

(1/2)x = 9/2

x = 9

the points are (0 , 9/2) and (9 , 0)

For the equation 3x - 4y = 12

when x = 0 , 3(0) - 4y = 12

-4y = 12

y = -3

when y = 0 , 3x -4(0) = 12

3x = 12

x = 4

the points are (0,-3) and (4,0) .

after plotting the lines on the graph , we can see that the both the lines intersect at the point (6 , 3/2) ,

Therefore , On solving the equations y = (-1/2)x + $4\frac{1}{2}$ and 3x - 4y = 12 graphically , the solution is (6 , 3/2) .

The given question is incomplete , the complete question is

Consider this equation y = (-1/2)x +  $4\frac{1}{2}$  and 3x - 4y = 12 .

Solve the system by graphing. label each graph.

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