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Mazyrski [523]
3 years ago
7

Simplifying the equation

Mathematics
1 answer:
TEA [102]3 years ago
4 0
1. x^15
2. m^40
3. v^7/2
4. k^4
5. 1/x^14
6. 1/r^3/2
7. b^25
8. h^2
9. m^3n^1/7
10. x^12
11. 1/g^37
12. 1/100m^6
13. j^6/216
14. 1/125f^3
15. 3z^1/2
16. 1/100m^6
17. j^6/216
18.1/81d^20
19. 1
20. g^1/2 r^3
21. 16a^11
22. m^16n^21
23. 1
24. 1/y^10x^6
25. 343s^10/t^17/2
26.n^17/2 /m^10/2
27. 729/b^24c^9
28. 20y^2/x^33
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Mr Coope drives 472 miles in 8 hours. At this rate, how many miles would he drive in 6
KatRina [158]
8hrs = 480mins
6hrs = 360 mins
472/480 = 0.983...
0.983... x 360 = 354
D) 354
6 0
3 years ago
Please help me with this one<br> 10x+5y=72<br> 15x+4y=80
Andre45 [30]
I hope this helps you

7 0
3 years ago
Read 2 more answers
Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select
Blizzard [7]

Answer:

Probability is:   $ \frac{\textbf{13}}{\textbf{51}} $

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $ \frac{number \hspace{1mm} of  \hspace{1mm} black  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm} of  \hspace{1mm} cards} $  $ = \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}} $

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $ \frac{number  \hspace{1mm} of  \hspace{1mm} red  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm}of  \hspace{1mm} cards} $  $ = \frac{26}{51}  $

Now, the probability of both black and red card = $ \frac{1}{2} \times \frac{26}{51} $

$ = \frac{\textbf{13}}{\textbf{51}} $

Hence, the answer.

5 0
4 years ago
Solve.
Tema [17]
From 1st equation
d + e = 2
d = 2 - e

From 2nd equation, subtitute d with 2 - e
d - e = 4
2 - e - e = 4
2 - 2e = 4
-2e = 2
e = -1

Find d
d = 2 - e
d = 2 - (-1)
d = 3

The solution is (3,-1)
4 0
3 years ago
Gieo 120 hạt giống của một loại cây thấy có 15 hạt nảy mầm. Với độ tin cậy 95% hãy tìm ước lượng khoảng cho tỷ lệ nảy mầm của lo
rosijanka [135]

Answer:

sorry can't understand the language

6 0
3 years ago
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