Answer:
here's the solution : -
=》2x - 3y = -29
=》x + 6y = 23
=》x = 23 - 6y
now, plugging the value of x in equation 1, we get : -
=》2x - 3y = -29
=》2 (23 - 6y) - 3y = - 29
=》46 - 12y - 3y = -29
=》-15y = -29 - 46
=》y = -75 ÷ -15
=》y = 5
now, plugging the value of y as 5 in equation 2
=》x + 6y = 23
=》x + (6 × 5.2) = 23
=》x = 23 - 30
=》x = - 7
Answer:
k= 1316/117
Step-by-step explanation:
Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Well 58.19 divided by 2.74 will equal 21 and random number after decimal so it will be 21 days
Answer:
False
Step-by-step explanation:
The lengths do not adhere to the triangle inequality theorem. Which states that the sum of the side lengths of any 2 sides of a triangle must exceed the length of the third side.
