9514 1404 393
Answer:
2) x = 7
3) x = 5
Step-by-step explanation:
When a transversal crosses parallel lines, all of the acute angles are congruent, and all of the obtuse angles are congruent. When it crosses at right angle, all of the angles are right angles.
2) All of the angles are right angles.
11x +13 = 90
11x = 77 . . . . . . subtract 13
x = 7 . . . . . . . divide by 11
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3) The two marked angles are acute.
16x = 80 . . . . the acute angles are congruent
x = 5 . . . . . . divide by 16
Answer:
The width which gives the greatest area is 7.5 yd
Step-by-step explanation:
This is an application of differential calculus. Given the area as a function of the width, we simply need to differentiate the function with respect to x and equate to zero which yields; 15-2x=0 since the slope of the graph is zero at the turning points. Solving for x yields, x=7.5 which indeed maximizes the area of the pen
A=850×(1+0.08)^(8)
A=1,573.29
Interest 1573.29-850=723.29
Answer:
Well isn't anyone able to write?
Is there measurements for AB AND CD