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3 years ago

5

Find how many years it would take for an investment of $3700 to grow to $6000 at an annual interest rate of 6.2% compounded semi

-annually.

1 answer:

lorasvet [3.4K]3 years ago

7 0

Answer:

7 years 11 months

Step-by-step explanation:

The future value formula for the value of a principal P invested at annual rate r compounded n times yearly for t years is ...

FV = P(1 +r/n)^(nt)

For the given numbers, we want to find t:

6000 = 3700(1 +.062/2)^(2t)

Dividing by 3700 and taking the logarithm, we get ...

6000/3700 = 1.031^(2t)

log(60/37) = 2t·log(1.031)

Dividing by the coefficient of t gives ...

t = log(60/37)/(2log(1.031)) ≈ 7.92 . . . . . years

It will take about 7 years 11 months for the investment to grow to $6000.

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What is an equation of the line that passes through the points (4, -1) and

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Answer:

y= x/2-3

Step-by-step explanation:

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4 years ago

A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev

Julli [10]

Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

462 + 330

= 792

8 0

3 years ago

An arithmetic sequence begins as follows: a1=13 a2=19 Which of the following gives the definition of its nth term?

Otrada [13]

Answer:

the nth term of the sequence is $a_n=6n+7$

Step-by-step explanation:

Given : An arithmetic sequence begins as follows: $a_1=13, a_2=19$

To find : Which of the following gives the definition of its nth term?

Solution :

The nth term of the A.P is $a_n=a+(n-1)d$

The first term is $a=a_1=13$

The common difference is $d=a_2-a_1$

$d=19-13=6$

Substitute in the formula,

$a_n=13+(n-1)6$

$a_n=13+6n-6$

$a_n=6n+7$

Therefore, the nth term of the sequence is $a_n=6n+7$

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3 years ago

1)Sheyna drive to the lake and back. It took two hours less time to get there than it did to get back. The average speed on the

ipn [44]

Answer:

8 hours

Step-by-step explanation:

Given:

Sheyna drives to the lake with average speed of 60 mph and

$v_1 = 60\ mph$

Sheyna drives back from the lake with average speed of 36 mph

$v_2 = 36\ mph$

It took 2 hours less time to get there than it did to get back.

Let $t_1$ be the time taken to drive to lake.

Let $t_2$ be the time taken to drive back from lake.

$t_2-t_1 = 2$ hrs ..... (1)

To find:

Total time taken = ?

$t_1+t_2 = ?$

Solution:

Let D be the distance to lake.

Formula for time is given as:

$Time =\dfrac{Distance}{Speed }$

$t_1 = \dfrac{D}{60}\ hrs$

$t_2 = \dfrac{D}{36}\ hrs$

Putting in equation (1):

$\dfrac{D}{36}-\dfrac{D}{60} = 2\\\Rightarrow \dfrac{5D-3D}{180} = 2\\\Rightarrow \dfrac{2D}{180} = 2\\\Rightarrow D = 180\ miles$

So,

$t_1 = \dfrac{180}{60}\ hrs = 3 \ hrs$

$t_2 = \dfrac{180}{36}\ hrs = 5\ hrs$

So, the answer is:

$t_1+t_2 = \bold{8\ hrs}$

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3 years ago

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levacccp [35]

Each term is being divided by -3, so the next three terms would be:

-1/3, 1/9, -1/27

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3 years ago