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yulyashka [42]
1 year ago
7

jenny has a box of candies with different flavors. she will randomly choose one piece of candy. the probability that she chooses

a strawberry-flavored piece is 611. what are the odds against her choosing a strawberry-flavored piece? 116
Mathematics
1 answer:
Sveta_85 [38]1 year ago
8 0

The odds against her choosing a strawberry-flavored piece is 5/11.

<h3>What is the probability?</h3>

Probability is the odds that a random event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The odds against her choosing a  strawberry-flavored piece = 1 - probability that she chooses a strawberry-flavored piece

The odds against her choosing a  strawberry-flavored piece = 1 - 6/11

The odds against her choosing a  strawberry-flavored piece = 5/11

Here is the complete question:

jenny has a box of candies with different flavors. she will randomly choose one piece of candy. the probability that she chooses a strawberry-flavored piece is 6/11. what are the odds against her choosing a strawberry-flavored piece?

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

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Steph,andra,emily,and becca are planning a road trip from their hometown to san antonio
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Answer:

a. Emily should begin her turn as the third driver at point (1, -0.5).

b. Emily's turn to drive end at point (-2.5, -3.75).

Step-by-step explanation:

Let assume that the group of girls travels from their hometown to San Antonio in a straight line. We know that each location is, respectively:

Hometown

H(x,y) = (8,6)

San Antonio

T(x,y) = (-6,-7)

Then, we can determine the end of each girl's turn to drive by the following vectorial expression based on the vectorial equation of the line:

Steph

S(x,y) = H(x,y) + \frac{1}{4}\cdot [T(x,y)-H(x,y)] (1)

S(x,y) = (8,6) + \frac{1}{4}\cdot [(-6,-7)-(8,6)]

S(x,y) = (8,6) +\frac{1}{4}\cdot (-14,-13)

S(x,y) = (4.5,2.75)

Andra

A(x,y) = H(x,y) + \frac{2}{4}\cdot [T(x,y)-H(x,y)] (2)

A(x,y) = (8,6) + \frac{2}{4}\cdot [(-6,-7)-(8,6)]

A(x,y) = (8,6)+\frac{2}{4}\cdot (-14,-13)

A(x,y) =(1, -0.5)

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E(x,y) = H(x,y) + \frac{3}{4}\cdot [T(x,y)-H(x,y)] (3)

E(x,y) = (8,6) + \frac{3}{4}\cdot [(-6,-7)-(8,6)]

E(x,y) = (8,6)+\frac{3}{4}\cdot (-14,-13)

E(x,y) = (-2.5, -3.75)

a. <em>If the girls take turns driving and each girl drives the same distance, at what point should they stop from Emily to begin her turn as the third driver? </em>

Emily's beginning point is the Andra's stop point, that is, A(x,y) =(1, -0.5).

Emily should begin her turn as the third driver at point (1, -0.5).

b. <em>At what point does Emily's turn to drive end?</em>

Emily's turn to drive end at point (-2.5, -3.75).

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