Answer: hewo, there! your answer is below
x= -5/4
or x= 8
Step-by-step explanation:
step 1: Subtract 27x+40 from both sides.
4x2−(27x+40)=27x+40−(27x+40)
4x2−27x−40=0
Step 2: Factor left side of equation.
(4x+5)(x−8)=0
Step 3: Set factors equal to 0.
4x+5=0 or x−8=0
hope this helps you
have a great Day
Plz makr branilest
Answer:
The class width is 20
Step-by-step explanation:
In a frequency or a relative frequency distribution the class width is calculated as the difference between the lower or upper class limits of consecutive classes. A point to note is that all the categories or classes usually have the same class width.
We use the first two classes to calculate the class width by using their respective upper limits;
Class width = 89 - 69
Class width = 20
Note that f(1) = 6(1)+2 = 8. Next, evaluate g(x) at x=8: g(f(1)) = g(8) = 2(8) + 4/5, or 16 4/5.
Radius of circle= 4
a) circle circumference=2(pi)r
circumference=2(pi)4=25.13
P=2W+2L
p=2(5)+2(10)
P=30
b) area of circle=pi(r^2)=pi(16)=50.27
area of rectangle=L×W= 5×10= 50
c) I think you can figure it put
